您可以使用这个函数-

function getStringInBetween(string, start , end) {
    // start and end will be excluded
    var indexOfStart = string.indexOf(start)
    indexOfStart = indexOfStart + start.length;
    var newString = string.slice(indexOfStart)
    var indexOfEnd = newString.indexOf(end)
    return newString.slice(0, indexOfEnd)
}

对于前-

let string = "<div class = 'mice'> I know how to code </div>"
let start = "<div class = 'mice'> "
let end = " </div>"
//then, getStringInBetween(string, start, end) returns "I know how to code"

下面的函数获取第一个匹配项

function getStringBetween(x: string, start: string, end: string) {
  const regex = new RegExp(`${start}(.*?)${end}`)

  if (regex.test(x)) {
    return regex.exec(x)![1]
  } else return undefined
}

有测试

test("getStringBetween", () => {
  const result = getStringBetween("<em> Jai Ram</em>", "<em>", "</em>")
  expect(result).toEqual(" Jai Ram")
  const result1 = getStringBetween(
    "hare Jai Ram hare hare hare",
    "hare",
    "hare"
  )
  expect(result1).toEqual(" Jai Ram ")
})

我喜欢这个方法:

var str = 'MyLongString:StringIWant;';
var tmpStr  = str.match(":(.*);");
var newStr = tmpStr[1];
//newStr now contains 'StringIWant'

你可以试试这个

var mySubString = str.substring(
    str.indexOf(":") + 1, 
    str.lastIndexOf(";")
);

上面的代码适用于简单的例子，但可以帮助… 使用打印稿。

参数

句子:你想要得到部分的字符串 第一个:开头字符(对于初始示例，它将是:) 最后:你的部分的最后一个字符(对于初始示例，它将是;)

输出

字符串数组(string[])。如果句子中没有好的部分，则返回[]。

Code

function getParts(sentence: string, first: string, last: string): string[] { 
  let goodParts: string[] = [];
  
  const allParts = sentence.split(first);

  allParts.forEach((part: string) => {
    if (part.indexOf(last) > -1) {
            const goodOne = (part.split(last))[0];
      goodParts = goodParts.concat(goodOne);
    }
  });
  
  return goodParts;
}

例子

const origin = "wrongString1:rightString1;wrongString2:rightString2;wrongString3:rightString3;wrongString4:rightString4;";

const result = getParts(origin, ':', ';');

console.log(result);
// ["rightString1", "rightString2", "rightString3", "rightString4"]

获取所有子字符串。

var out = []; 'MyLongString:StringIWant;'
.replace(/(:)\w+(;)+/g, (e) => {
    out.push(e.replace(':', '').replace(';', ''))
    return e;
});
console.log(out[0])