我翻遍了苹果的iBook,找不到任何关于它的定义:
有人能解释一下dispatch_after的结构吗?
dispatch_after(<#when: dispatch_time_t#>, <#queue: dispatch_queue_t?#>, <#block: dispatch_block_t?#>)
我翻遍了苹果的iBook,找不到任何关于它的定义:
有人能解释一下dispatch_after的结构吗?
dispatch_after(<#when: dispatch_time_t#>, <#queue: dispatch_queue_t?#>, <#block: dispatch_block_t?#>)
当前回答
以下是Swift中asyncAfter的同步版本:
let deadline = DispatchTime.now() + .seconds(3)
let semaphore = DispatchSemaphore.init(value: 0)
DispatchQueue.global().asyncAfter(deadline: deadline) {
dispatchPrecondition(condition: .onQueue(DispatchQueue.global()))
semaphore.signal()
}
semaphore.wait()
与异步的一起:
let deadline = DispatchTime.now() + .seconds(3)
DispatchQueue.main.asyncAfter(deadline: deadline) {
dispatchPrecondition(condition: .onQueue(DispatchQueue.global()))
}
其他回答
1)添加这个方法作为UIViewController Extension的一部分。
extension UIViewController{
func runAfterDelay(delay: NSTimeInterval, block: dispatch_block_t) {
let time = dispatch_time(DISPATCH_TIME_NOW, Int64(delay * Double(NSEC_PER_SEC)))
dispatch_after(time, dispatch_get_main_queue(), block)
}
}
在VC上调用这个方法:
self.runAfterDelay(5.0, block: {
//Add code to this block
print("run After Delay Success")
})
2)
performSelector("yourMethod Name", withObject: nil, afterDelay: 1)
3)
override func viewWillAppear(animated: Bool) {
dispatch_after(dispatch_time(DISPATCH_TIME_NOW, 2), dispatch_get_main_queue(), { () -> () in
//Code Here
})
/ /紧凑的形式
dispatch_after(dispatch_time(DISPATCH_TIME_NOW, 2), dispatch_get_main_queue()) {
//Code here
}
}
Swift 3和4:
您可以在DispatchQueue上创建一个扩展,并在内部添加使用DispatchQueue asyncAfter函数的函数delay
extension DispatchQueue {
static func delay(_ delay: DispatchTimeInterval, closure: @escaping () -> ()) {
let timeInterval = DispatchTime.now() + delay
DispatchQueue.main.asyncAfter(deadline: timeInterval, execute: closure)
}
}
使用:
DispatchQueue.delay(.seconds(1)) {
print("This is after delay")
}
现在在Swift的中央调度(GCD)中异步调度不仅仅是语法糖。
添加Podfile
pod 'AsyncSwift'
然后,你可以这样使用它。
let seconds = 3.0
Async.main(after: seconds) {
print("Is called after 3 seconds")
}.background(after: 6.0) {
print("At least 3.0 seconds after previous block, and 6.0 after Async code is called")
}
我总是喜欢使用扩展而不是自由函数。
斯威夫特4
public extension DispatchQueue {
private class func delay(delay: TimeInterval, closure: @escaping () -> Void) {
let when = DispatchTime.now() + delay
DispatchQueue.main.asyncAfter(deadline: when, execute: closure)
}
class func performAction(after seconds: TimeInterval, callBack: @escaping (() -> Void) ) {
DispatchQueue.delay(delay: seconds) {
callBack()
}
}
}
按以下方法使用。
DispatchQueue.performAction(after: 0.3) {
// Code Here
}
Swift 4有一个很短的方法来做到这一点:
Timer.scheduledTimer(withTimeInterval: 2, repeats: false) { (timer) in
// Your stuff here
print("hello")
}