下面的代码来自jQuery UI自动完成:
var projects = [
{
value: "jquery",
label: "jQuery",
desc: "the write less, do more, JavaScript library",
icon: "jquery_32x32.png"
},
{
value: "jquery-ui",
label: "jQuery UI",
desc: "the official user interface library for jQuery",
icon: "jqueryui_32x32.png"
},
{
value: "sizzlejs",
label: "Sizzle JS",
desc: "a pure-JavaScript CSS selector engine",
icon: "sizzlejs_32x32.png"
}
];
例如,我想更改jquery-ui的desc值。我该怎么做呢?
此外,是否有更快的方法来获取数据?我的意思是给对象一个名字来获取它的数据,就像数组中的对象一样?比如jquery-ui。jquery-ui。desc = ....
let users = [
{id: 1, name: 'Benedict'},
{id: 2, name: 'Myles'},
{id: 3, name: 'Happy'},
]
users.map((user, index) => {
if(user.id === 1){
users[index] = {id: 1, name: 'Baba Benny'};
}
return user
})
console.log(users)
这段代码所做的是映射对象,然后匹配所需的
使用if语句,
if(user.id === 1)
一旦有匹配的地方使用它的索引交换
users[index] = {id: 1, name: 'Baba Benny'};
对象,然后返回修改后的数组
根据以下数据,我们想用西瓜替换summerFruits列表中的浆果。
const summerFruits = [
{id:1,name:'apple'},
{id:2, name:'orange'},
{id:3, name: 'berries'}];
const fruit = {id:3, name: 'watermelon'};
有两种方法。
第一种方法:
//create a copy of summer fruits.
const summerFruitsCopy = [...summerFruits];
//find index of item to be replaced
const targetIndex = summerFruits.findIndex(f=>f.id===3);
//replace the object with a new one.
summerFruitsCopy[targetIndex] = fruit;
第二种方法:使用map和spread:
const summerFruitsCopy = summerFruits.map(fruitItem =>
fruitItem .id === fruit.id ?
{...summerFruits, ...fruit} : fruitItem );
summerFruitsCopy列表现在将返回一个更新对象的数组。