是否可以使用一些代码获得设备的IP地址?


当前回答

private InetAddress getLocalAddress()throws IOException {

            try {
                for (Enumeration<NetworkInterface> en = NetworkInterface.getNetworkInterfaces(); en.hasMoreElements();) {
                    NetworkInterface intf = en.nextElement();
                    for (Enumeration<InetAddress> enumIpAddr = intf.getInetAddresses(); enumIpAddr.hasMoreElements();) {
                        InetAddress inetAddress = enumIpAddr.nextElement();
                        if (!inetAddress.isLoopbackAddress()) {
                            //return inetAddress.getHostAddress().toString();
                            return inetAddress;
                        }
                    }
                }
            } catch (SocketException ex) {
                Log.e("SALMAN", ex.toString());
            }
            return null;
        }

其他回答

你可以使用LinkProperties。建议用于新的Android版本。

此功能检索WiFi和移动数据的本地IP地址。它需要Manifest.permission。ACCESS_NETWORK_STATE许可。

@Nullable
public static String getDeviceIpAddress(@NonNull ConnectivityManager connectivityManager) {
    LinkProperties linkProperties = connectivityManager.getLinkProperties(connectivityManager.getActiveNetwork());
    InetAddress inetAddress;
    for(LinkAddress linkAddress : linkProperties.getLinkAddresses()) {
        inetAddress = linkAddress.getAddress();
        if (inetAddress instanceof Inet4Address
                && !inetAddress.isLoopbackAddress()
                && inetAddress.isSiteLocalAddress()) {
            return inetAddress.getHostAddress();
        }
    }
    return null;
}

这是互联网上最简单的方法…… 首先,将此权限添加到您的manifest文件中…

“互联网” “ACCESS_NETWORK_STATE”

将此添加到Activity的onCreate文件中。

getPublicIP();

现在将这个函数添加到MainActivity.class中。

private void getPublicIP() { ArrayList<String> urls=new ArrayList<String>(); //to read each line new Thread(new Runnable(){ public void run(){ //TextView t; //to show the result, please declare and find it inside onCreate() try { // Create a URL for the desired page URL url = new URL("https://api.ipify.org/"); //My text file location //First open the connection HttpURLConnection conn=(HttpURLConnection) url.openConnection(); conn.setConnectTimeout(60000); // timing out in a minute BufferedReader in = new BufferedReader(new InputStreamReader(conn.getInputStream())); //t=(TextView)findViewById(R.id.TextView1); // ideally do this in onCreate() String str; while ((str = in.readLine()) != null) { urls.add(str); } in.close(); } catch (Exception e) { Log.d("MyTag",e.toString()); } //since we are in background thread, to post results we have to go back to ui thread. do the following for that PermissionsActivity.this.runOnUiThread(new Runnable(){ public void run(){ try { Toast.makeText(PermissionsActivity.this, "Public IP:"+urls.get(0), Toast.LENGTH_SHORT).show(); } catch (Exception e){ Toast.makeText(PermissionsActivity.this, "TurnOn wiffi to get public ip", Toast.LENGTH_SHORT).show(); } } }); } }).start(); }

最近,一个IP地址仍然由getLocalIpAddress()返回,尽管与网络断开连接(没有服务指示器)。说明“设置>关于话机>状态”中显示的IP地址与应用程序想象的不一致。

我之前已经通过添加以下代码实现了一个解决方案:

ConnectivityManager cm = getConnectivityManager();
NetworkInfo net = cm.getActiveNetworkInfo();
if ((null == net) || !net.isConnectedOrConnecting()) {
    return null;
}

有谁听过吗?

虽然有一个正确的答案,我在这里分享我的答案,希望这样会更方便。

WifiManager wifiMan = (WifiManager) context.getSystemService(Context.WIFI_SERVICE);
WifiInfo wifiInf = wifiMan.getConnectionInfo();
int ipAddress = wifiInf.getIpAddress();
String ip = String.format("%d.%d.%d.%d", (ipAddress & 0xff),(ipAddress >> 8 & 0xff),(ipAddress >> 16 & 0xff),(ipAddress >> 24 & 0xff));

这是这个答案的返工,去掉了不相关的信息,添加了有用的评论,更清楚地命名变量,并改进了逻辑。

不要忘记包含以下权限:

<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

InternetHelper.java:

public class InternetHelper {

    /**
     * Get IP address from first non-localhost interface
     *
     * @param useIPv4 true=return ipv4, false=return ipv6
     * @return address or empty string
     */
    public static String getIPAddress(boolean useIPv4) {
        try {
            List<NetworkInterface> interfaces =
                    Collections.list(NetworkInterface.getNetworkInterfaces());

            for (NetworkInterface interface_ : interfaces) {

                for (InetAddress inetAddress :
                        Collections.list(interface_.getInetAddresses())) {

                    /* a loopback address would be something like 127.0.0.1 (the device
                       itself). we want to return the first non-loopback address. */
                    if (!inetAddress.isLoopbackAddress()) {
                        String ipAddr = inetAddress.getHostAddress();
                        boolean isIPv4 = ipAddr.indexOf(':') < 0;

                        if (isIPv4 && !useIPv4) {
                            continue;
                        }
                        if (useIPv4 && !isIPv4) {
                            int delim = ipAddr.indexOf('%'); // drop ip6 zone suffix
                            ipAddr = delim < 0 ? ipAddr.toUpperCase() :
                                    ipAddr.substring(0, delim).toUpperCase();
                        }
                        return ipAddr;
                    }
                }

            }
        } catch (Exception ignored) { } // if we can't connect, just return empty string
        return "";
    }

    /**
     * Get IPv4 address from first non-localhost interface
     *
     * @return address or empty string
     */
    public static String getIPAddress() {
        return getIPAddress(true);
    }

}