是否可以使用一些代码获得设备的IP地址?
当前回答
老实说,我对代码安全只是有点熟悉,所以这可能有点像黑客。但对我来说,这是最通用的方法:
package com.my_objects.ip;
import java.net.InetAddress;
import java.net.UnknownHostException;
public class MyIpByHost
{
public static void main(String a[])
{
try
{
InetAddress host = InetAddress.getByName("nameOfDevice or webAddress");
System.out.println(host.getHostAddress());
}
catch (UnknownHostException e)
{
e.printStackTrace();
}
} }
其他回答
在Kotlin中,没有Formatter
private fun getIPAddress(useIPv4 : Boolean): String {
try {
var interfaces = Collections.list(NetworkInterface.getNetworkInterfaces())
for (intf in interfaces) {
var addrs = Collections.list(intf.getInetAddresses());
for (addr in addrs) {
if (!addr.isLoopbackAddress()) {
var sAddr = addr.getHostAddress();
var isIPv4: Boolean
isIPv4 = sAddr.indexOf(':')<0
if (useIPv4) {
if (isIPv4)
return sAddr;
} else {
if (!isIPv4) {
var delim = sAddr.indexOf('%') // drop ip6 zone suffix
if (delim < 0) {
return sAddr.toUpperCase()
}
else {
return sAddr.substring(0, delim).toUpperCase()
}
}
}
}
}
}
} catch (e: java.lang.Exception) { }
return ""
}
在你的活动中,下面的函数getIpAddress(context)返回电话的IP地址:
public static String getIpAddress(Context context) {
WifiManager wifiManager = (WifiManager) context.getApplicationContext()
.getSystemService(WIFI_SERVICE);
String ipAddress = intToInetAddress(wifiManager.getDhcpInfo().ipAddress).toString();
ipAddress = ipAddress.substring(1);
return ipAddress;
}
public static InetAddress intToInetAddress(int hostAddress) {
byte[] addressBytes = { (byte)(0xff & hostAddress),
(byte)(0xff & (hostAddress >> 8)),
(byte)(0xff & (hostAddress >> 16)),
(byte)(0xff & (hostAddress >> 24)) };
try {
return InetAddress.getByAddress(addressBytes);
} catch (UnknownHostException e) {
throw new AssertionError();
}
}
方法getDeviceIpAddress返回设备的ip地址,如果连接了wifi接口,则首选wifi接口地址。
@NonNull
private String getDeviceIpAddress() {
String actualConnectedToNetwork = null;
ConnectivityManager connManager = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
if (connManager != null) {
NetworkInfo mWifi = connManager.getNetworkInfo(ConnectivityManager.TYPE_WIFI);
if (mWifi.isConnected()) {
actualConnectedToNetwork = getWifiIp();
}
}
if (TextUtils.isEmpty(actualConnectedToNetwork)) {
actualConnectedToNetwork = getNetworkInterfaceIpAddress();
}
if (TextUtils.isEmpty(actualConnectedToNetwork)) {
actualConnectedToNetwork = "127.0.0.1";
}
return actualConnectedToNetwork;
}
@Nullable
private String getWifiIp() {
final WifiManager mWifiManager = (WifiManager) getApplicationContext().getSystemService(Context.WIFI_SERVICE);
if (mWifiManager != null && mWifiManager.isWifiEnabled()) {
int ip = mWifiManager.getConnectionInfo().getIpAddress();
return (ip & 0xFF) + "." + ((ip >> 8) & 0xFF) + "." + ((ip >> 16) & 0xFF) + "."
+ ((ip >> 24) & 0xFF);
}
return null;
}
@Nullable
public String getNetworkInterfaceIpAddress() {
try {
for (Enumeration<NetworkInterface> en = NetworkInterface.getNetworkInterfaces(); en.hasMoreElements(); ) {
NetworkInterface networkInterface = en.nextElement();
for (Enumeration<InetAddress> enumIpAddr = networkInterface.getInetAddresses(); enumIpAddr.hasMoreElements(); ) {
InetAddress inetAddress = enumIpAddr.nextElement();
if (!inetAddress.isLoopbackAddress() && inetAddress instanceof Inet4Address) {
String host = inetAddress.getHostAddress();
if (!TextUtils.isEmpty(host)) {
return host;
}
}
}
}
} catch (Exception ex) {
Log.e("IP Address", "getLocalIpAddress", ex);
}
return null;
}
编译一些想法,以更好的kotlin解决方案从WifiManager获得wifi ip:
private fun getWifiIp(context: Context): String? {
return context.getSystemService<WifiManager>().let {
when {
it == null -> "No wifi available"
!it.isWifiEnabled -> "Wifi is disabled"
it.connectionInfo == null -> "Wifi not connected"
else -> {
val ip = it.connectionInfo.ipAddress
((ip and 0xFF).toString() + "." + (ip shr 8 and 0xFF) + "." + (ip shr 16 and 0xFF) + "." + (ip shr 24 and 0xFF))
}
}
}
}
或者,您可以通过NetworkInterface获取ip4环回设备的ip地址:
fun getNetworkIp4LoopbackIps(): Map<String, String> = try {
NetworkInterface.getNetworkInterfaces()
.asSequence()
.associate { it.displayName to it.ip4LoopbackIps() }
.filterValues { it.isNotEmpty() }
} catch (ex: Exception) {
emptyMap()
}
private fun NetworkInterface.ip4LoopbackIps() =
inetAddresses.asSequence()
.filter { !it.isLoopbackAddress && it is Inet4Address }
.map { it.hostAddress }
.filter { it.isNotEmpty() }
.joinToString()
最近,一个IP地址仍然由getLocalIpAddress()返回,尽管与网络断开连接(没有服务指示器)。说明“设置>关于话机>状态”中显示的IP地址与应用程序想象的不一致。
我之前已经通过添加以下代码实现了一个解决方案:
ConnectivityManager cm = getConnectivityManager();
NetworkInfo net = cm.getActiveNetworkInfo();
if ((null == net) || !net.isConnectedOrConnecting()) {
return null;
}
有谁听过吗?
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