在我的例子中，我不想创建一个新的活动只是为了显示2秒的图像。当启动我的MainActivity，图像被加载到持有者使用毕加索，我知道这需要大约1秒的加载，所以我决定做以下在我的MainActivity OnCreate:

splashImage = (ImageView) findViewById(R.id.spllll);

    this.getWindow().setFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN,WindowManager.LayoutParams.FLAG_FULLSCREEN);

    int secondsDelayed = 1;
    new Handler().postDelayed(new Runnable() {
        public void run() {
            getWindow().clearFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN);
            splashImage.setVisibility(View.GONE);

        }
    }, secondsDelayed * 2000);

当启动应用程序时，发生的第一件事是显示ImageView，并通过将窗口标志设置为全屏来删除状态栏。然后我使用Handler运行2秒，2秒后我清除全屏标志，并设置ImageView的可见性为GONE。简单，简单，有效。

有时用户打开SplashActivity并立即退出，但应用程序仍然在SPLASH_SCREEN_DISPLAY_LENGTH后转到MainActivity。

为了防止它:在SplashActivity中，你应该在移动到MainActivity之前检查SplashActivity是否结束

public class SplashActivity extends Activity {

    private final int SPLASH_SCREEN_DISPLAY_LENGTH = 2000;

    @Override
    public void onCreate(Bundle icicle) {
        ...
        new Handler().postDelayed(new Runnable() {
            @Override
            public void run() {

                if (!isFinishing()) {//isFinishing(): If the activity is finishing, returns true; else returns false.
                    startActivity(new Intent(SplashActivity.this, MainActivity.class));
                    finish();
                }

            }, SPLASH_SCREEN_DISPLAY_LENGTH);
        }                             
   }                                
}

希望这对你有所帮助

启动画面示例:

public class MainActivity extends Activity {
    private ImageView splashImageView;
    boolean splashloading = false;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        splashImageView = new ImageView(this);
        splashImageView.setScaleType(ScaleType.FIT_XY);
        splashImageView.setImageResource(R.drawable.ic_launcher);
        setContentView(splashImageView);
        splashloading = true;
        Handler h = new Handler();
        h.postDelayed(new Runnable() {
            public void run() {
                splashloading = false;
                setContentView(R.layout.activity_main);
            }

        }, 3000);

    }

}

简单的代码，它的工作:)简单的飞溅

int secondsDelayed = 1;
    new Handler().postDelayed(new Runnable() {
        public void run() {
            startActivity(new Intent(LoginSuccessFull.this, LoginActivity.class));
            finish();
        }
    }, secondsDelayed * 1500);

Create an Activity SplashScreen.java public class SplashScreen extends Activity { protected boolean _active = true; protected int _splashTime = 3000; // time to display the splash screen in ms @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.splashscreen); Thread splashTread = new Thread() { @Override public void run() { try { int waited = 0; while (_active && (waited < _splashTime)) { sleep(100); if (_active) { waited += 100; } } } catch (Exception e) { } finally { startActivity(new Intent(SplashScreen.this, MainActivity.class)); finish(); } }; }; splashTread.start(); } } splashscreen.xml will be like this <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="600px" android:layout_height="1024px" android:background="#FF0000"> </RelativeLayout>

在Kotlin中编写以下代码:-

 Handler().postDelayed({
            val mainIntent = Intent(this@SplashActivity, LoginActivity::class.java)
            startActivity(mainIntent)
            finish()
        }, 500)

希望这对你有所帮助，谢谢........