我想让我的应用看起来更专业,所以我决定添加一个启动画面。
我应该如何进行实现呢?
我想让我的应用看起来更专业,所以我决定添加一个启动画面。
我应该如何进行实现呢?
当前回答
public class MainActivity extends Activity {
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Thread t=new Thread()
{
public void run()
{
try {
sleep(2000);
finish();
Intent cv=new Intent(MainActivity.this,HomeScreen.class/*otherclass*/);
startActivity(cv);
}
catch (InterruptedException e) {
e.printStackTrace();
}
}
};
t.start();
}
其他回答
我在android中使用线程制作Flash屏幕。
import android.content.Intent;
import android.os.Bundle;
import android.support.annotation.Nullable;
import android.support.v7.app.AppCompatActivity;
public class HomeScreen extends AppCompatActivity{
@Override
protected void onCreate(@Nullable Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.screen_home);
Thread thread = new Thread(){
public void run(){
try {
Thread.sleep(3 * 1000);
Intent i = new Intent(HomeScreen.this, MainActivity.class);
startActivity(i);
} catch (InterruptedException e) {
}
}
};
thread.start();
}
}
Create an activity: Splash Create a layout XML file: splash.xml Put UI components in the splash.xml layout so it looks how you want your Splash.java may look like this: public class Splash extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.splash); int secondsDelayed = 1; new Handler().postDelayed(new Runnable() { public void run() { startActivity(new Intent(Splash.this, ActivityB.class)); finish(); } }, secondsDelayed * 1000); } } change ActivityB.class to whichever activity you want to start after the splash screen check your manifest file and it should look like
<活动 android: name = "。屏” android: label = " @string / app_name " > > < /活动 <活动 android: name = "。飞溅” android: label = " @string / title_activity_splash_screen " > <意图过滤器> <action android:name="android.intent.action. main " /> <category android:name="android.intent.category. launcher " /> < /意图过滤器> > < /活动
在Android中,启动画面是一个有点不可用的对象:为了隐藏主活动启动的延迟,它不能尽快加载。使用它有两个原因:广告和网络运营。
实现为对话框使跳跃没有延迟从启动画面到主UI的活动。
public class SplashDialog extends Dialog {
ImageView splashscreen;
SplashLoader loader;
int splashTime = 4000;
public SplashDialog(Context context, int theme) {
super(context, theme);
}
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_splash);
setCancelable(false);
new Handler().postDelayed(new Runnable() {
@Override
public void run() {
cancel();
}
}, splashTime);
}
}
布局:
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:background="@color/white">
<ImageView
android:id="@+id/splashscreen"
android:layout_width="190dp"
android:layout_height="190dp"
android:background="@drawable/whistle"
android:layout_centerInParent="true" />
</RelativeLayout>
并开始:
public class MyActivity extends ActionBarActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
if (getIntent().getCategories() != null && getIntent().getCategories().contains("android.intent.category.LAUNCHER")) {
showSplashScreen();
}
}
protected Dialog splashDialog;
protected void showSplashScreen() {
splashDialog = new SplashDialog(this, R.style.SplashScreen);
splashDialog.show();
}
...
}
它真的很简单,在安卓,我们只是使用处理器的概念来实现启动画面
在SplashScreenActivity java文件中粘贴此代码。
在SplashScreenActivity xml文件中使用imageview放置任何图片。
public void LoadScreen() {
final Handler handler = new Handler();
handler.postDelayed(new Runnable() {
@Override
public void run() {
Intent i = new Intent(SplashScreenActivity.this, AgilanbuGameOptionsActivity.class);
startActivity(i);
}
}, 2000);
}
创建一个活动,让我们活动命名为“a”,然后创建一个名为mysscreen .xml的xml文件,在其中设置一个启动画面图像作为背景,然后使用倒计时计时器从一个活动导航到另一个活动。要知道如何使用倒计时定时器看到我的答案在这个问题的TimerTask在Android?