我需要在Java中连接两个字符串数组。

void f(String[] first, String[] second) {
    String[] both = ???
}

哪种方法最简单?


当前回答

这是可行的,但您需要插入自己的错误检查。

public class StringConcatenate {

    public static void main(String[] args){

        // Create two arrays to concatenate and one array to hold both
        String[] arr1 = new String[]{"s","t","r","i","n","g"};
        String[] arr2 = new String[]{"s","t","r","i","n","g"};
        String[] arrBoth = new String[arr1.length+arr2.length];

        // Copy elements from first array into first part of new array
        for(int i = 0; i < arr1.length; i++){
            arrBoth[i] = arr1[i];
        }

        // Copy elements from second array into last part of new array
        for(int j = arr1.length;j < arrBoth.length;j++){
            arrBoth[j] = arr2[j-arr1.length];
        }

        // Print result
        for(int k = 0; k < arrBoth.length; k++){
            System.out.print(arrBoth[k]);
        }

        // Additional line to make your terminal look better at completion!
        System.out.println();
    }
}

它可能不是最有效的,但除了Java自己的API之外,它不依赖其他任何东西。

其他回答

在Java 8中使用流:

String[] both = Stream.concat(Arrays.stream(a), Arrays.stream(b))
                      .toArray(String[]::new);

或者像这样,使用flatMap:

String[] both = Stream.of(a, b).flatMap(Stream::of)
                      .toArray(String[]::new);

要对泛型类型执行此操作,必须使用反射:

@SuppressWarnings("unchecked")
T[] both = Stream.concat(Arrays.stream(a), Arrays.stream(b)).toArray(
    size -> (T[]) Array.newInstance(a.getClass().getComponentType(), size));

我看到许多带有公共静态T[]concat(T[]a,T[]b){}等签名的通用答案,但据我所知,这些答案只适用于Object数组,而不适用于基元数组。下面的代码既适用于对象数组,也适用于基元数组,使其更通用。。。

public static <T> T concat(T a, T b) {
        //Handles both arrays of Objects and primitives! E.g., int[] out = concat(new int[]{6,7,8}, new int[]{9,10});
        //You get a compile error if argument(s) not same type as output. (int[] in example above)
        //You get a runtime error if output type is not an array, i.e., when you do something like: int out = concat(6,7);
        if (a == null && b == null) return null;
        if (a == null) return b;
        if (b == null) return a;
        final int aLen = Array.getLength(a);
        final int bLen = Array.getLength(b);
        if (aLen == 0) return b;
        if (bLen == 0) return a;
        //From here on we really need to concatenate!

        Class componentType = a.getClass().getComponentType();
        final T result = (T)Array.newInstance(componentType, aLen + bLen);
        System.arraycopy(a, 0, result, 0, aLen);
        System.arraycopy(b, 0, result, aLen, bLen);
        return result;
    }

    public static void main(String[] args) {
        String[] out1 = concat(new String[]{"aap", "monkey"}, new String[]{"rat"});
        int[] out2 = concat(new int[]{6,7,8}, new int[]{9,10});
    }
ArrayList<String> both = new ArrayList(Arrays.asList(first));
both.addAll(Arrays.asList(second));

both.toArray(new String[0]);

只是想添加,您也可以使用System.arraycopy:

import static java.lang.System.out;
import static java.lang.System.arraycopy;
import java.lang.reflect.Array;
class Playground {
    @SuppressWarnings("unchecked")
    public static <T>T[] combineArrays(T[] a1, T[] a2) {
        T[] result = (T[]) Array.newInstance(a1.getClass().getComponentType(), a1.length+a2.length);
        arraycopy(a1,0,result,0,a1.length);
        arraycopy(a2,0,result,a1.length,a2.length);
        return result;
    }
    public static void main(String[ ] args) {
        String monthsString = "JANFEBMARAPRMAYJUNJULAUGSEPOCTNOVDEC";
        String[] months = monthsString.split("(?<=\\G.{3})");
        String daysString = "SUNMONTUEWEDTHUFRISAT";
        String[] days = daysString.split("(?<=\\G.{3})");
        for (String m : months) {
            out.println(m);
        }
        out.println("===");
         for (String d : days) {
            out.println(d);
        }
        out.println("===");
        String[] results = combineArrays(months, days);
        for (String r : results) {
            out.println(r);
        }
        out.println("===");
    }
}

这可能是唯一通用且类型安全的方法:

public class ArrayConcatenator<T> {
    private final IntFunction<T[]> generator;

    private ArrayConcatenator(IntFunction<T[]> generator) {
        this.generator = generator;
    }

    public static <T> ArrayConcatenator<T> concat(IntFunction<T[]> generator) {
        return new ArrayConcatenator<>(generator);
    }

    public T[] apply(T[] array1, T[] array2) {
        T[] array = generator.apply(array1.length + array2.length);
        System.arraycopy(array1, 0, array, 0, array1.length);
        System.arraycopy(array2, 0, array, array1.length, array2.length);
        return array;
    }
}

用法非常简洁:

Integer[] array1 = { 1, 2, 3 };
Double[] array2 = { 4.0, 5.0, 6.0 };
Number[] array = concat(Number[]::new).apply(array1, array2);

(需要静态导入)

拒绝无效的数组类型:

concat(String[]::new).apply(array1, array2); // error
concat(Integer[]::new).apply(array1, array2); // error