我最终使用了这个正则表达式，因为它成功地验证了逗号、注释、Unicode字符和IP(v4)域地址。

有效地址为:

“@example。org (评论)test@example。org тест@example。org ტესტი@example。org test@[192.168 . 1章1段]

 public const string REGEX_EMAIL = @"^(((\([\w!#$%&'*+\/=?^_`{|}~-]*\))?[^<>()[\]\\.,;:\s@\""]+(\.[^<>()[\]\\.,;:\s@\""]+)*)|(\"".+\""))(\([\w!#$%&'*+\/=?^_`{|}~-]*\))?@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$";

我从第1条中得到Phil的答案，并创建了这个类。 这样调用它:bool isValid = Validator.EmailIsValid(emailString);

下面是这个类:

using System.Text.RegularExpressions;

public static class Validator
{

    static Regex ValidEmailRegex = CreateValidEmailRegex();

    /// <summary>
    /// Taken from http://haacked.com/archive/2007/08/21/i-knew-how-to-validate-an-email-address-until-i.aspx
    /// </summary>
    /// <returns></returns>
    private static Regex CreateValidEmailRegex()
    {
        string validEmailPattern = @"^(?!\.)(""([^""\r\\]|\\[""\r\\])*""|"
            + @"([-a-z0-9!#$%&'*+/=?^_`{|}~]|(?<!\.)\.)*)(?<!\.)"
            + @"@[a-z0-9][\w\.-]*[a-z0-9]\.[a-z][a-z\.]*[a-z]$";

        return new Regex(validEmailPattern, RegexOptions.IgnoreCase);
    }

    internal static bool EmailIsValid(string emailAddress)
    {
        bool isValid = ValidEmailRegex.IsMatch(emailAddress);

        return isValid;
    }
}

    /// <summary>
    /// Validates the email if it follows the valid email format
    /// </summary>
    /// <param name="emailAddress"></param>
    /// <returns></returns>
    public static bool EmailIsValid(string emailAddress)
    {
        //if string is not null and empty then check for email follow the format
        return string.IsNullOrEmpty(emailAddress)?false : new Regex(@"^(?!\.)(""([^""\r\\]|\\[""\r\\])*""|([-a-z0-9!#$%&'*+/=?^_`{|}~]|(?<!\.)\.)*)(?<!\.)@[a-z0-9][\w\.-]*[a-z0-9]\.[a-z][a-z\.]*[a-z]$", RegexOptions.IgnoreCase).IsMatch(emailAddress);
    }

在“尝试块”发送一个验证电子邮件。 让用户打开电子邮件并单击一个链接，以验证电子邮件是真实的。

在此过程成功完成之前，该电子邮件被认为是无效的。

我写了一个函数来检查电子邮件是否有效。在大多数情况下，这似乎对我很有效。

结果:

dasddas-@.com => FALSE
-asd@das.com => FALSE
as3d@dac.coas- => FALSE
dsq!a?@das.com => FALSE
_dasd@sd.com => FALSE
dad@sds => FALSE
asd-@asd.com => FALSE
dasd_-@jdas.com => FALSE
asd@dasd@asd.cm => FALSE
da23@das..com => FALSE
_dasd_das_@9.com => FALSE

d23d@da9.co9 => TRUE
dasd.dadas@dasd.com => TRUE
dda_das@das-dasd.com => TRUE
dasd-dasd@das.com.das => TRUE

代码:

    private bool IsValidEmail(string email)
    {
        bool valid = false;
        try
        {
            var addr = new System.Net.Mail.MailAddress(email);
            valid = true;
        }
        catch
        {
            valid = false;
            goto End_Func;
        }

        valid = false;
        int pos_at = email.IndexOf('@');
        char checker = Convert.ToChar(email.Substring(pos_at + 1, 1));
        var chars = "qwertyuiopasdfghjklzxcvbnm0123456789";
        foreach (char chr in chars)
        {
            if (checker == chr)
            {
                valid = true;
                break;
            }
        }
        if (valid == false)
        {
            goto End_Func;
        } 

        int pos_dot = email.IndexOf('.', pos_at + 1);
        if(pos_dot == -1)
        {
            valid = false;
            goto End_Func;
        }

        valid = false;
        try
        {
            checker = Convert.ToChar(email.Substring(pos_dot + 1, 1));
            foreach (char chr in chars)
            {
                if (checker == chr)
                {
                    valid = true;
                    break;
                }
            }
        }
        catch
        {
            valid = false;
            goto End_Func;
        }

        Regex valid_checker = new Regex(@"^[a-zA-Z0-9_@.-]*$");
        valid = valid_checker.IsMatch(email);
        if (valid == false)
        {
            goto End_Func;
        }

        List<int> pos_list = new List<int> { };
        int pos = 0;
        while (email.IndexOf('_', pos) != -1)
        {
            pos_list.Add(email.IndexOf('_', pos));
            pos = email.IndexOf('_', pos) + 1;
        }

        pos = 0;
        while (email.IndexOf('.', pos) != -1)
        {
            pos_list.Add(email.IndexOf('.', pos));
            pos = email.IndexOf('.', pos) + 1;
        }

        pos = 0;
        while (email.IndexOf('-', pos) != -1)
        {
            pos_list.Add(email.IndexOf('-', pos));
            pos = email.IndexOf('-', pos) + 1;
        }

        int sp_cnt = pos_list.Count();
        pos_list.Sort();
        for (int i = 0; i < sp_cnt - 1; i++)
        {
            if (pos_list[i] + 1 == pos_list[i + 1])
            {
                valid = false;
                break;
            }

            if (pos_list[i]+1 == pos_at || pos_list[i]+1 == pos_dot)
            {
                valid = false;
                break;
            }
        }

        if(valid == false)
        {
            goto End_Func;
        }

        if (pos_list[sp_cnt - 1] == email.Length - 1 || pos_list[0] == 0)
        {
            valid = false;
        }

    End_Func:;
        return valid;
    }

我是来偷电子邮件的验证码的。然后我发现答案中的代码不必要地扩展了。我相信我用最短的方式写出了最好的解决方案:

public static bool IsEmail(string email)
{
    try
    {
        return new System.Net.Mail.MailAddress(email).Address == email && !email.Trim().EndsWith(".");
    }
    catch
    {
        return false;
    }
}