我将Poyson 1的答案简化如下:

public static bool IsValidEmailAddress(string candidateEmailAddr)
{
    string regexExpresion = "\\w+([-+.']\\w+)*@\\w+([-.]\\w+)*\\.\\w+([-.]\\w+)*";
    return (Regex.IsMatch(candidateEmailAddr, regexExpresion)) && 
           (Regex.Replace(candidateEmailAddr, regexExpresion, string.Empty).Length == 0);
}

我从第1条中得到Phil的答案，并创建了这个类。 这样调用它:bool isValid = Validator.EmailIsValid(emailString);

下面是这个类:

using System.Text.RegularExpressions;

public static class Validator
{

    static Regex ValidEmailRegex = CreateValidEmailRegex();

    /// <summary>
    /// Taken from http://haacked.com/archive/2007/08/21/i-knew-how-to-validate-an-email-address-until-i.aspx
    /// </summary>
    /// <returns></returns>
    private static Regex CreateValidEmailRegex()
    {
        string validEmailPattern = @"^(?!\.)(""([^""\r\\]|\\[""\r\\])*""|"
            + @"([-a-z0-9!#$%&'*+/=?^_`{|}~]|(?<!\.)\.)*)(?<!\.)"
            + @"@[a-z0-9][\w\.-]*[a-z0-9]\.[a-z][a-z\.]*[a-z]$";

        return new Regex(validEmailPattern, RegexOptions.IgnoreCase);
    }

    internal static bool EmailIsValid(string emailAddress)
    {
        bool isValid = ValidEmailRegex.IsMatch(emailAddress);

        return isValid;
    }
}

我最终使用了这个正则表达式，因为它成功地验证了逗号、注释、Unicode字符和IP(v4)域地址。

有效地址为:

“@example。org (评论)test@example。org тест@example。org ტესტი@example。org test@[192.168 . 1章1段]

 public const string REGEX_EMAIL = @"^(((\([\w!#$%&'*+\/=?^_`{|}~-]*\))?[^<>()[\]\\.,;:\s@\""]+(\.[^<>()[\]\\.,;:\s@\""]+)*)|(\"".+\""))(\([\w!#$%&'*+\/=?^_`{|}~-]*\))?@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$";

通过system . text . regulareexpressions检查电子邮件字符串的格式是否正确:

    public static bool IsValidEmailId(string InputEmail)
    {
        Regex regex = new Regex(@"^([\w\.\-]+)@([\w\-]+)((\.(\w){2,3})+)$");
        Match match = regex.Match(InputEmail);
        if (match.Success)
            return true;
        else
            return false;
    }

    protected void Email_TextChanged(object sender, EventArgs e)
    {
        String UserEmail = Email.Text;
        if (IsValidEmailId(UserEmail))
        {
            Label4.Text = "This email is correct formate";
        }
        else
        {
            Label4.Text = "This email isn't correct formate";
        }
    }

我认为最好的方法如下:

    public static bool EmailIsValid(string email)
    {
        string expression = "\\w+([-+.']\\w+)*@\\w+([-.]\\w+)*\\.\\w+([-.]\\w+)*";

        if (Regex.IsMatch(email, expression))
        {
            if (Regex.Replace(email, expression, string.Empty).Length == 0)
            {
                return true;
            }
        }
        return false;
    }

你可以在一个通用类中使用这个静态函数。

对@齿轮回答做了一点修改

public static bool IsValidEmail(this string email)
{
  // skip the exception & return early if possible
  if (email.IndexOf("@") <= 0) return false;

  try
  {
    var address = new MailAddress(email);
    return address.Address == email;
  }
  catch
  {
    return false;
  }
}