我需要一个滚动窗口(又名滑动窗口)可迭代的序列/迭代器/生成器。(默认的Python迭代可以被认为是一种特殊情况，其中窗口长度为1。)我目前正在使用以下代码。我怎样才能做得更优雅和/或更有效?
def rolling_window(seq, window_size):
it = iter(seq)
win = [it.next() for cnt in xrange(window_size)] # First window
yield win
for e in it: # Subsequent windows
win[:-1] = win[1:]
win[-1] = e
yield win
if __name__=="__main__":
for w in rolling_window(xrange(6), 3):
print w
"""Example output:
[0, 1, 2]
[1, 2, 3]
[2, 3, 4]
[3, 4, 5]
"""
对于window_size == 2的特定情况(即，在序列中迭代相邻的重叠对)，请参见如何从列表中迭代重叠(当前，下一个)值对?
我喜欢t ():
from itertools import tee, izip
def window(iterable, size):
iters = tee(iterable, size)
for i in xrange(1, size):
for each in iters[i:]:
next(each, None)
return izip(*iters)
for each in window(xrange(6), 3):
print list(each)
给:
[0, 1, 2]
[1, 2, 3]
[2, 3, 4]
[3, 4, 5]
def GetShiftingWindows(thelist, size):
return [ thelist[x:x+size] for x in range( len(thelist) - size + 1 ) ]
>> a = [1, 2, 3, 4, 5]
>> GetShiftingWindows(a, 3)
[ [1, 2, 3], [2, 3, 4], [3, 4, 5] ]
如何使用以下方法:
mylist = [1, 2, 3, 4, 5, 6, 7]
def sliding_window(l, window_size=2):
if window_size > len(l):
raise ValueError("Window size must be smaller or equal to the number of elements in the list.")
t = []
for i in xrange(0, window_size):
t.append(l[i:])
return zip(*t)
print sliding_window(mylist, 3)
输出:
[(1, 2, 3), (2, 3, 4), (3, 4, 5), (4, 5, 6), (5, 6, 7)]
我的两个版本的窗口实现
from typing import Sized, Iterable
def window(seq: Sized, n: int, strid: int = 1, drop_last: bool = False):
for i in range(0, len(seq), strid):
res = seq[i:i + n]
if drop_last and len(res) < n:
break
yield res
def window2(seq: Iterable, n: int, strid: int = 1, drop_last: bool = False):
it = iter(seq)
result = []
step = 0
for i, ele in enumerate(it):
result.append(ele)
result = result[-n:]
if len(result) == n:
if step % strid == 0:
yield result
step += 1
if not drop_last:
yield result
#Importing the numpy library
import numpy as np
arr = np.arange(6) #Sequence
window_size = 3
np.lib.stride_tricks.as_strided(arr, shape= (len(arr) - window_size +1, window_size),
strides = arr.strides*2)
"""Example output:
[0, 1, 2]
[1, 2, 3]
[2, 3, 4]
[3, 4, 5]
"""
