闲聊：

在类Test中有一个类方法，返回一个常量字符串:

method1
    ^ 'niko'

无论发生什么，这个方法都会不断返回字符串'niko'。但事实并非如此。

s := Test method1 

(设置为“niko”。)

s at: 4 put: $i.

(设置为“niki”。)

s := Test method1

(再次设置为“niki”。)

因此，第二行代码永久地将method1更改为返回'niki'而不是'niko'，即使方法的源代码没有更新。

通知7。一个有效程序的例子:

    Chomsky is a room. 
    A thought is a kind of thing. 
    Color is a kind of value. 
    The colors are red, green and blue. 
    A thought has a color. It is usually Green. 
    A thought can be colorful or colorless. It is usually colorless. 
    An idea is a thought in Chomsky with description "Colorless green ideas sleep furiously." 
    A manner is a kind of thing. 
    Furiously is a manner. 
    Sleeping relates one thought to one manner. 
    The verb to sleep (he sleeps, they sleep, he slept, it is slept, he is sleeping) implies the sleeping relation. 
    Colorless green ideas sleep furiously. 

像图灵机模拟器这样的其他愚蠢的东西可以找到。

在ruby/python/c中，你可以像这样连接字符串:

a = "foo" "bar"
print a # => "foobar"

在C或c++中，sizeof…参数的圆括号是可选的。假设参数不是类型:

void foo() {
  int int_inst;

  // usual style - brackets ...
  size_t a = sizeof(int);
  size_t b = sizeof(int_inst);
  size_t c = sizeof(99);

  // but ...
  size_t d = sizeof int_inst; // this is ok
  // size_t e = sizeof int; // this is NOT ok
  size_t f = sizeof 99; // this is also ok
}

我一直不明白这是为什么!

在PHP中，函数名不区分大小写。这可能会导致您认为php中的所有标识符都不区分大小写。再猜一遍。变量区分大小写。WTF。

function add($a, $b)
{
    return $a + $b;
}

$foo = add(1, 2);
$Foo = Add(3, 4);

echo "foo is $foo"; // outputs foo is 3
echo "Foo is $Foo"; // outputs Foo is 7

我有点纠结:

1;

在perl中，模块需要返回true。