我需要通过GPS程序获得我的当前位置。 我怎样才能做到呢?


当前回答

我已经发布了一个小的库,可以很容易地在Android中获取位置数据,它甚至照顾到Android M运行时权限。

您可以在这里查看它:https://github.com/julioromano/RxLocation并使用它或其源代码作为实现的示例。

其他回答

简单的找到写代码在位置方法

public void onLocationChanged(Location location) {
    if (mCurrLocationMarker != null) {
        mCurrLocationMarker.remove();
    }


    //Place current location marker
    LatLng latLng = new LatLng(location.getLatitude(), location.getLongitude());
    MarkerOptions markerOptions = new MarkerOptions();
    markerOptions.position(latLng);
    markerOptions.title("Current Position");
    markerOptions.icon(BitmapDescriptorFactory.defaultMarker(BitmapDescriptorFactory.HUE_RED));
    mCurrLocationMarker = mMap.addMarker(markerOptions);

    //move map camera
    mMap.moveCamera(CameraUpdateFactory.newLatLng(latLng));
    mMap.animateCamera(CameraUpdateFactory.zoomTo(18));

    PolylineOptions pOptions = new PolylineOptions()
            .width(5)
            .color(Color.GREEN)
            .geodesic(true);
    for (int z = 0; z < routePoints.size(); z++) {
        LatLng point = routePoints.get(z);
        pOptions.add(point);
    }
    line = mMap.addPolyline(pOptions);
    routePoints.add(latLng);
}

自2020年9月23日起,play-services-location版本17.1.0包含了FusedLocationProviderClient.getCurrentLocation()方法,这是获得当前位置的推荐和直接的方法:

返回设备上的单个当前位置固定。与返回缓存位置的getLastLocation()不同,此方法可能导致设备上的活动位置计算。如果能在合理的时间内(几十秒)确定设备位置,将返回一个新的位置,否则将返回null。

关于详细的例子,看看codingjeremy的回答和GitHub上的官方Android位置示例- Current location (Kotlin)。

class MyLocation {
    Timer timer1;
    LocationManager lm;
    LocationResult locationResult;
    boolean gps_enabled = false;
    boolean network_enabled = false;

    public boolean getLocation(Context context, LocationResult result) {
        // I use LocationResult callback class to pass location value from
        // MyLocation to user code.
        locationResult = result;
        if (lm == null)
            lm = (LocationManager) context
                    .getSystemService(Context.LOCATION_SERVICE);

        // Exceptions will be thrown if the provider is not permitted.
        try {
            gps_enabled = lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
        }
        catch (Exception ex) {
        }
        try {
            network_enabled = lm
                    .isProviderEnabled(LocationManager.NETWORK_PROVIDER);
        }
        catch (Exception ex) {
        }

        // Don't start listeners if no provider is enabled.
        if (!gps_enabled && !network_enabled)
            return false;

        if (gps_enabled)
            lm.requestLocationUpdates(LocationManager.GPS_PROVIDER, 0, 0,
                    locationListenerGps);
        if (network_enabled)
            lm.requestLocationUpdates(LocationManager.NETWORK_PROVIDER, 0, 0,
                    locationListenerNetwork);
        timer1 = new Timer();
        timer1.schedule(new GetLastLocation(), 5000);
        return true;
    }

    LocationListener locationListenerGps = new LocationListener() {
        public void onLocationChanged(Location location) {
            timer1.cancel();
            locationResult.gotLocation(location);
            lm.removeUpdates(this);
            lm.removeUpdates(locationListenerNetwork);
        }

        public void onProviderDisabled(String provider) {
        }

        public void onProviderEnabled(String provider) {
        }

        public void onStatusChanged(String provider, int status, Bundle extras) {
        }
    };

    LocationListener locationListenerNetwork = new LocationListener() {
        public void onLocationChanged(Location location) {
            timer1.cancel();
            locationResult.gotLocation(location);
            lm.removeUpdates(this);
            lm.removeUpdates(locationListenerGps);
        }

        public void onProviderDisabled(String provider) {
        }

        public void onProviderEnabled(String provider) {
        }

        public void onStatusChanged(String provider, int status, Bundle extras) {
        }
    };

    class GetLastLocation extends TimerTask {
        @Override
        public void run() {
            lm.removeUpdates(locationListenerGps);
            lm.removeUpdates(locationListenerNetwork);

            Location net_loc = null, gps_loc = null;
            if (gps_enabled)
                gps_loc = lm.getLastKnownLocation(LocationManager.GPS_PROVIDER);
            if (network_enabled)
                net_loc = lm
                        .getLastKnownLocation(LocationManager.NETWORK_PROVIDER);

            // If there are both values, use the latest one.
            if (gps_loc != null && net_loc != null) {
                if (gps_loc.getTime() > net_loc.getTime())
                    locationResult.gotLocation(gps_loc);
                else
                    locationResult.gotLocation(net_loc);
                return;
            }

            if (gps_loc != null) {
                locationResult.gotLocation(gps_loc);
                return;
            }
            if (net_loc != null) {
                locationResult.gotLocation(net_loc);
                return;
            }
            locationResult.gotLocation(null);
        }
    }

    public static abstract class LocationResult {
        public abstract void gotLocation(Location location);
    }
}

我希望这对你有所帮助……

如果你正在为Android创建新的位置项目,你应该使用新的谷歌Play位置服务。它更准确,使用起来更简单。

几年来,我一直致力于一个开源的GPS跟踪器项目,GpsTracker。我最近更新了它,以处理来自Android、iOS、Windows Phone和Java ME手机的定期更新。它功能齐全,可以满足您的需要,并且拥有MIT许可证。

GpsTracker中的Android项目使用了新的谷歌播放服务,还有两个服务器堆栈(ASP。NET和PHP)来让你追踪这些手机。

GoogleSamples有详细的例子使用最新的FusedLocationProviderApi。 不幸的是,被点赞最多的答案都过时了。

按照下面的例子使用FusedLocationProviderApi实现位置服务

https://github.com/googlesamples/android-play-location/tree/master/LocationUpdates

https://github.com/googlesamples/android-play-location/blob/master/LocationUpdates/app/src/main/java/com/google/android/gms/location/sample/locationupdates/MainActivity.java