在安卓系统中防止双击按钮的最佳方法是什么?


当前回答

下面是一个OnClickListener代理,它可以根据qezt的答案阻止连续的单击。

import android.os.SystemClock;
import android.view.View;

public class MultiClickGuard implements View.OnClickListener {    

    private long mLastClickTime;

    private final int mThresholdMillis;
    private final View.OnClickListener mListener;

    public MultiClickGuard(View.OnClickListener listener, int thresholdMillis) {
        if (listener == null) {
            throw new NullPointerException("Null OnClickListener");
        }
        if (thresholdMillis < 0) {
            throw new IllegalArgumentException("Negative click threshold: " + thresholdMillis);
        }

        mListener = listener;
        mThresholdMillis = thresholdMillis;
    }

    @Override
    public void onClick(View v) {
        // Using a time threshold to prevent successive clicks.
        if (SystemClock.elapsedRealtime() - mLastClickTime < mThresholdMillis) {
            return;
        }
        mLastClickTime = SystemClock.elapsedRealtime();

        // Forward the click event to the *real* listener.
        mListener.onClick(v);
    }
}

用法示例

button.setOnClickListener(new MultiClickGuard(new View.OnClickListener() {
    @Override
    public void onClick(View v) {
        // do something
    }
}, 1000));

button.setOnClickListener(new MultiClickGuard(v -> {...}, 1000));
button.setOnClickListener(new MultiClickGuard(v -> doSomething(), 1000));

在试图阻止启动一个活动的多个实例的情况下,考虑指定启动模式:理解任务和返回堆栈,这是可靠的方式。

如果您试图阻止打开一个对话框片段的多个实例,您可以检查片段管理器是否已经包含了对话框,例如getSupportFragmentManager(). findfragmentbytag (tag)。

其他回答

更可取的解决方案是,

onclick(){
  btn.setEnabled(false);
  btn.setClickable(false);
  //yourwork
  myWork();
}

myWork(){
 //your tasks.
 btn.setEnabled(true);
 btn.setClickable(true);
}

由于一个环节很容易被忽略,我不得不一遍又一遍地重复这个环节

如果有人还在寻找一个简短的答案,你可以使用下面的代码

 private static long mLastClickTime = 0;
  if (SystemClock.elapsedRealtime() - mLastClickTime < 1000) { // 1000 = 1second
         return;
    }
 mLastClickTime = SystemClock.elapsedRealtime();

当用户在1秒内单击View时,这段代码将进入if语句,然后返回;将被启动,而进一步的代码将不会被启动。

如果点击按钮,你正在打开一个新的片段,只需添加android:clickable="true"到正在打开的新片段的根视图。

我的解决方案(Kotlin):

class OnDebouncedClickListener(private val delayInMilliSeconds: Long, val action: () -> Unit) : View.OnClickListener {
    var enable = true

    override fun onClick(view: View?) {
        if (enable) {
            enable = false
            view?.postDelayed(delayInMilliSeconds) { enable = true }
            action()
        }
    }
}

fun View.setOnDebouncedClickListener(delayInMilliSeconds: Long = 500, action: () -> Unit) {
    val onDebouncedClickListener = OnDebouncedClickListener(delayInMilliSeconds, action)
    setOnClickListener(onDebouncedClickListener)
}

使用:

button.apply {       
            setOnDebouncedClickListener {
                //your action on click
            }
        }

Setting the button as clickable false upon clicking and true once it is desired to make the button clickable again is the right approach. For instance, consider the following scenario: you are making a service call upon click of a button and once the service is done you want to display a dialog. For this, once the button is clicked you can set setClickable(false) and once the service responds you will do setClicklable(true) through a reference you pass to your custom dialog. When dialog invokes isShowing() you can trigger the listener and setClicklable(true).