下面的代码是一个相当通用的解决方案，也有一个时间消耗和剩余时间估计。你可以使用任何可迭代对象。进度条的大小固定为25个字符，但可以使用完整、半块和四分之一块字符以1%的速度显示更新。输出如下所示:

 18% |████▌                    | \ [0:00:01, 0:00:06]

代码示例:

import sys, time
from numpy import linspace

def ProgressBar(iterObj):
  def SecToStr(sec):
    m, s = divmod(sec, 60)
    h, m = divmod(m, 60)
    return u'%d:%02d:%02d'%(h, m, s)
  L = len(iterObj)
  steps = {int(x):y for x,y in zip(linspace(0, L, min(100,L), endpoint=False),
                                   linspace(0, 100, min(100,L), endpoint=False))}
  qSteps = ['', u'\u258E', u'\u258C', u'\u258A'] # quarter and half block chars
  startT = time.time()
  timeStr = '   [0:00:00, -:--:--]'
  activity = [' -',' \\',' |',' /']
  for nn,item in enumerate(iterObj):
    if nn in steps:
      done = u'\u2588'*int(steps[nn]/4.0)+qSteps[int(steps[nn]%4)]
      todo = ' '*(25-len(done))
      barStr = u'%4d%% |%s%s|'%(steps[nn], done, todo)
    if nn>0:
      endT = time.time()
      timeStr = ' [%s, %s]'%(SecToStr(endT-startT),
                             SecToStr((endT-startT)*(L/float(nn)-1)))
    sys.stdout.write('\r'+barStr+activity[nn%4]+timeStr); sys.stdout.flush()
    yield item
  barStr = u'%4d%% |%s|'%(100, u'\u2588'*25)
  timeStr = '   [%s, 0:00:00]\n'%(SecToStr(time.time()-startT))
  sys.stdout.write('\r'+barStr+timeStr); sys.stdout.flush()

# Example
s = ''
for c in ProgressBar(list('Disassemble and reassemble this string')):
  time.sleep(0.2)
  s += c
print(s)

欢迎提出改进建议或其他意见。干杯!

如果你的工作不能被分解成可测量的块，你可以在一个新的线程中调用你的函数，并记录它所花费的时间:

import thread
import time
import sys

def work():
    time.sleep( 5 )

def locked_call( func, lock ):
    lock.acquire()
    func()
    lock.release()

lock = thread.allocate_lock()
thread.start_new_thread( locked_call, ( work, lock, ) )

# This part is icky...
while( not lock.locked() ):
    time.sleep( 0.1 )

while( lock.locked() ):
    sys.stdout.write( "*" )
    sys.stdout.flush()
    time.sleep( 1 )
print "\nWork Done"

显然，您可以根据需要提高计时精度。

使用这个库:fish (GitHub)。

用法:

>>> import fish
>>> while churning:
...     churn_churn()
...     fish.animate()

玩得开心!

已经有很多好的答案，但添加这个特定的基于@HandyGold75的答案，我希望它在特定的上下文中是callabe，有一个初始的msg，加上在结束时的几秒钟的时间反馈。

from time import sleep, time


class ProgressBar:
    def __init__(self, total: float, width: int = 50, msg: str = ""):
    self.total = total
    self.width = width
    self.start: float = time()
    if msg:
        print(f"{msg}")

    def progress(self, progress: float):
        percent = self.width * ((progress) / self.total)
        bar = chr(9608) * int(percent) + "-" * (self.width - int(percent))
        print(
            f"\r|{bar}| {(100/self.width)*percent:.2f}% "
            f"[{progress} of {self.total}]",
            end="\r",
        )

    def __enter__(self):
        return self.progress

    def __exit__(self, type, value, traceback):
        end: float = time()
        print(f"\nFinished after {end - self.start: .3f} seconds.")


# USAGE
total_loops = 150
with ProgressBar(total=total_loops) as progress:
    for i in range(total_loops):
        sleep(0.01)  # Do something usefull here
        progress(i + 1)

我使用wget，如果在mac或linux上，你必须在windows或终端中的cmd提示符中安装模块

pip install wget

这非常简单，只需使用download()函数即可

import wget
url = input("Enter Url to download: ")
wget.download(url)

TQDM也是一个选择，你也必须下载这个模块。

pip install tqdm

现在确保导入模块，设置范围和pass

from tqdm import tqdm
for i in tqdm(range(int(9e7))):
    pass

iterrows的Progressbar。调整了@eusoubrasileiro代码，用于在循环遍历数据帧的行时显示进度。此外还显示百分比、ith/count、经过秒数、eps /sec、剩余秒数。允许指定第n个更新计数。

import time
import sys
def progressbar_iterrows(df, prefix="", size=60, file=sys.stdout, per=1000):
    count = len(df)
    t = 0
    def show(j,elapsed):
        avg = 0 if elapsed == 0 else j/elapsed
        remaining = 0 if avg == 0 else (count-j)/avg
        x = int(size*j/count)
        file.write("%s[%s%s] %i%% %i/%i elapsed:%i %i/sec remaining:%i\r" % (prefix, "#"*x, "."*(size-x), j/count, j, count, elapsed, avg, remaining))
        file.flush()
    file.write("Initializing ...\r")
    file.flush()
    for i, item in df.iterrows():
        yield i,item
        if t == 0:
            t = time.time()
        if i % per == 0:
            show(i,time.time()-t)
    file.write("\n")
    file.flush()

用法:

    for n,r in progressbar_iterrows(br_b_sections_df, "Processed: "):
        # do something

输出:

Processed: [........................] 0% 5000/28751240 elapsed:12 413/sec remaining:55054