如果你使用express.js，

app.post('/get/ip/address', function (req, res) {
      res.send(req.ip);
})

以下函数涵盖了所有的情况，将会有所帮助

var ip;
if (req.headers['x-forwarded-for']) {
    ip = req.headers['x-forwarded-for'].split(",")[0];
} else if (req.connection && req.connection.remoteAddress) {
    ip = req.connection.remoteAddress;
} else {
    ip = req.ip;
}console.log("client IP is *********************" + ip);

对于我使用kubernetes ingress (NGINX):

req.headers['x-original-forwarded-for']

在Node.js中非常有效

如果你有多个ip，这对我来说是可行的:

Var ipaddress = (req。标题(“x-forwarded-for”)| | req.connection.remoteAddress | | req.socket.remoteAddress | | req.connection.socket.remoteAddress) .split (", ") [0];

函数getCallerIP(请求){ Var IP = request。标题(“x-forwarded-for”)| | request.connection.remoteAddress | | request.socket.remoteAddress | | request.connection.socket.remoteAddress; IP = IP .split('，')[0]; IP = IP .split(':').slice(-1);//如果IP以“::ffff:146.xxx.xxx.xxx”格式返回 返回的ip; ｝

你可以像这样快速获取用户Ip

req.ip

在这个例子中，我们获取了用户的Ip，然后用req.ip把它发回给用户

app.get('/', (req, res)=> { 
    res.send({ ip : req.ip})
    
})