我要实现这个:

public static bool Retry(int maxRetries, Func<bool, bool> method)
{
    while (maxRetries > 0)
    {
        if (method(maxRetries == 1))
        {
            return true;
        }
        maxRetries--;
    }
    return false;        
}

我不会像在其他例子中那样使用异常。在我看来，如果我们期待一种方法不会成功的可能性，那么它的失败也不是例外。我调用的方法如果成功就返回true，失败就返回false。

为什么它是Func<bool>而不是Func<bool>?因此，如果我希望一个方法能够在失败时抛出异常，我有一种方法可以通知它这是最后一次尝试。

因此，我可能会将它用于如下代码:

Retry(5, delegate(bool lastIteration)
   {
       // do stuff
       if (!succeeded && lastIteration)
       {
          throw new InvalidOperationException(...)
       }
       return succeeded;
   });

or

if (!Retry(5, delegate(bool lastIteration)
   {
       // do stuff
       return succeeded;
   }))
{
   Console.WriteLine("Well, that didn't work.");
}

如果传递一个方法不使用的参数被证明很尴尬，那么实现一个重载的Retry也很简单，它只接受Func<bool>。

在之前工作的基础上，我考虑用三种方式增强重试逻辑:

Specifying what exception type to catch/retry. This is the primary enhacement as retrying for any exception is just plain wrong. Not nesting the last try in a try/catch, achieving slightly better performance Making it an Action extension method static class ActionExtensions { public static void InvokeAndRetryOnException<T> (this Action action, int retries, TimeSpan retryDelay) where T : Exception { if (action == null) throw new ArgumentNullException("action"); while( retries-- > 0 ) { try { action( ); return; } catch (T) { Thread.Sleep( retryDelay ); } } action( ); } }

然后可以像这样调用方法(当然也可以使用匿名方法):

new Action( AMethodThatMightThrowIntermittentException )
  .InvokeAndRetryOnException<IntermittentException>( 2, TimeSpan.FromSeconds( 1 ) );

允许函数和重试消息

public static T RetryMethod<T>(Func<T> method, int numRetries, int retryTimeout, Action onFailureAction)
{
 Guard.IsNotNull(method, "method");            
 T retval = default(T);
 do
 {
   try
   {
     retval = method();
     return retval;
   }
   catch
   {
     onFailureAction();
      if (numRetries <= 0) throw; // improved to avoid silent failure
      Thread.Sleep(retryTimeout);
   }
} while (numRetries-- > 0);
  return retval;
}

下面是一个async/await版本，它可以聚合异常并支持取消。

/// <seealso href="https://learn.microsoft.com/en-us/azure/architecture/patterns/retry"/>
protected static async Task<T> DoWithRetry<T>( Func<Task<T>> action, CancellationToken cancelToken, int maxRetries = 3 )
{
    var exceptions = new List<Exception>();

    for ( int retries = 0; !cancelToken.IsCancellationRequested; retries++ )
        try {
            return await action().ConfigureAwait( false );
        } catch ( Exception ex ) {
            exceptions.Add( ex );

            if ( retries < maxRetries )
                await Task.Delay( 500, cancelToken ).ConfigureAwait( false ); //ease up a bit
            else
                throw new AggregateException( "Retry limit reached", exceptions );
        }

    exceptions.Add( new OperationCanceledException( cancelToken ) );
    throw new AggregateException( "Retry loop was canceled", exceptions );
}

对于那些既想对任何异常进行重试，又想显式设置异常类型的人，可以使用以下方法:

public class RetryManager 
{
    public void Do(Action action, 
                    TimeSpan interval, 
                    int retries = 3)
    {
        Try<object, Exception>(() => {
            action();
            return null;
        }, interval, retries);
    }

    public T Do<T>(Func<T> action, 
                    TimeSpan interval, 
                    int retries = 3)
    {
        return Try<T, Exception>(
              action
            , interval
            , retries);
    }

    public T Do<E, T>(Func<T> action, 
                       TimeSpan interval, 
                       int retries = 3) where E : Exception
    {
        return Try<T, E>(
              action
            , interval
            , retries);
    }

    public void Do<E>(Action action, 
                       TimeSpan interval, 
                       int retries = 3) where E : Exception
    {
        Try<object, E>(() => {
            action();
            return null;
        }, interval, retries);
    }

    private T Try<T, E>(Func<T> action, 
                       TimeSpan interval, 
                       int retries = 3) where E : Exception
    {
        var exceptions = new List<E>();

        for (int retry = 0; retry < retries; retry++)
        {
            try
            {
                if (retry > 0)
                    Thread.Sleep(interval);
                return action();
            }
            catch (E ex)
            {
                exceptions.Add(ex);
            }
        }

        throw new AggregateException(exceptions);
    }
}

6年后更新:现在我认为下面的方法非常糟糕。为了创建重试逻辑，我们应该考虑使用Polly这样的库。

重试方法的异步实现:

public static async Task<T> DoAsync<T>(Func<dynamic> action, TimeSpan retryInterval, int retryCount = 3)
    {
        var exceptions = new List<Exception>();

        for (int retry = 0; retry < retryCount; retry++)
        {
            try
            {
                return await action().ConfigureAwait(false);
            }
            catch (Exception ex)
            {
                exceptions.Add(ex);
            }

            await Task.Delay(retryInterval).ConfigureAwait(false);
        }
        throw new AggregateException(exceptions);
    }

重点:我使用。configureawait (false);和Func<dynamic>代替Func<T>