我有一系列的图片,我想从中创建一个视频。理想情况下,我可以为每帧指定帧持续时间,但固定的帧速率也可以。我在wxPython中这样做,所以我可以渲染到wxDC或我可以将图像保存到文件,如PNG。是否有一个Python库,将允许我创建一个视频(AVI, MPG等)或一个动画GIF从这些帧?

编辑:我已经尝试过PIL,它似乎不起作用。有人能用这个结论来纠正我吗?这个链接似乎支持我关于PIL的结论:http://www.somethinkodd.com/oddthinking/2005/12/06/python-imaging-library-pil-and-animated-gifs/


当前回答

我尝试了以下方法,非常有用:

首先下载Figtodat和images2gif库到本地目录。

其次,收集数组中的图形并将其转换为动画gif:

import sys
sys.path.insert(0,"/path/to/your/local/directory")
import Figtodat
from images2gif import writeGif
import matplotlib.pyplot as plt
import numpy

figure = plt.figure()
plot   = figure.add_subplot (111)

plot.hold(False)
    # draw a cardinal sine plot
images=[]
y = numpy.random.randn(100,5)
for i in range(y.shape[1]):
    plot.plot (numpy.sin(y[:,i]))  
    plot.set_ylim(-3.0,3)
    plot.text(90,-2.5,str(i))
    im = Figtodat.fig2img(figure)
    images.append(im)

writeGif("images.gif",images,duration=0.3,dither=0)

其他回答

老问题,有很多很好的答案,但可能仍然对另一种选择感兴趣……

我最近在github (https://github.com/WarrenWeckesser/numpngw)上发布的numpngw模块可以从numpy数组写入动画PNG文件。(更新:numpngw现在在pypi: https://pypi.python.org/pypi/numpngw。)

例如,这个脚本:

import numpy as np
import numpngw


img0 = np.zeros((64, 64, 3), dtype=np.uint8)
img0[:32, :32, :] = 255
img1 = np.zeros((64, 64, 3), dtype=np.uint8)
img1[32:, :32, 0] = 255
img2 = np.zeros((64, 64, 3), dtype=np.uint8)
img2[32:, 32:, 1] = 255
img3 = np.zeros((64, 64, 3), dtype=np.uint8)
img3[:32, 32:, 2] = 255
seq = [img0, img1, img2, img3]
for img in seq:
    img[16:-16, 16:-16] = 127
    img[0, :] = 127
    img[-1, :] = 127
    img[:, 0] = 127
    img[:, -1] = 127

numpngw.write_apng('foo.png', seq, delay=250, use_palette=True)

创建:

你需要一个支持动画PNG的浏览器(直接或带有插件)才能看到动画。

我使用images2gif.py,这很容易使用。它似乎是文件大小的两倍。

26个110kb的PNG文件,我期望26*110kb = 2860kb,但my_gif.GIF是5.7mb

另外,因为GIF是8位的,好看的png在GIF中变得有点模糊

下面是我使用的代码:

__author__ = 'Robert'
from images2gif import writeGif
from PIL import Image
import os

file_names = sorted((fn for fn in os.listdir('.') if fn.endswith('.png')))
#['animationframa.png', 'animationframb.png', 'animationframc.png', ...] "

images = [Image.open(fn) for fn in file_names]

print writeGif.__doc__
# writeGif(filename, images, duration=0.1, loops=0, dither=1)
#    Write an animated gif from the specified images.
#    images should be a list of numpy arrays of PIL images.
#    Numpy images of type float should have pixels between 0 and 1.
#    Numpy images of other types are expected to have values between 0 and 255.


#images.extend(reversed(images)) #infinit loop will go backwards and forwards.

filename = "my_gif.GIF"
writeGif(filename, images, duration=0.2)
#54 frames written
#
#Process finished with exit code 0

以下是26帧中的3帧:

缩小图像会减小尺寸:

size = (150,150)
for im in images:
    im.thumbnail(size, Image.ANTIALIAS)

Smart Manoj回答:从文件夹中的所有图像制作一个.mp4电影

安装:

pip install imageio-ffmpeg
pip install imageio

代码:

import os
import imageio

root = r'path_to_folder_with_images'

images = []    
for subdir, dirs, files in os.walk(root):
    for file in files:
        images.append(imageio.imread(os.path.join(root,file)))

savepath = r'path_to_save_folder'
imageio.mimsave(os.path.join(savepath,'movie.mp4'), images)

PS:确保你的“文件”列表按照你想要的方式排序,如果你已经相应地保存了你的图像,你会节省一些时间

下面是如何使用PIL (install with: pip install Pillow):

import glob
import contextlib
from PIL import Image

# filepaths
fp_in = "/path/to/image_*.png"
fp_out = "/path/to/image.gif"

# use exit stack to automatically close opened images
with contextlib.ExitStack() as stack:

    # lazily load images
    imgs = (stack.enter_context(Image.open(f))
            for f in sorted(glob.glob(fp_in)))

    # extract  first image from iterator
    img = next(imgs)

    # https://pillow.readthedocs.io/en/stable/handbook/image-file-formats.html#gif
    img.save(fp=fp_out, format='GIF', append_images=imgs,
             save_all=True, duration=200, loop=0)

查看文档:https://pillow.readthedocs.io/en/stable/handbook/image-file-formats.html#gif

该任务可以通过在与图片文件序列相同的文件夹中运行两行python脚本来完成。对于png格式的文件,脚本是-

from scitools.std import movie
movie('*.png',fps=1,output_file='thisismygif.gif')