是否有一种方法可以获取类实例上存在的属性列表?
class new_class():
def __init__(self, number):
self.multi = int(number) * 2
self.str = str(number)
a = new_class(2)
print(', '.join(a.SOMETHING))
期望的结果是输出"multi, str"。我希望它能看到脚本各个部分的当前属性。
是否有一种方法可以获取类实例上存在的属性列表?
class new_class():
def __init__(self, number):
self.multi = int(number) * 2
self.str = str(number)
a = new_class(2)
print(', '.join(a.SOMETHING))
期望的结果是输出"multi, str"。我希望它能看到脚本各个部分的当前属性。
当前回答
请参阅已按顺序执行的python shell脚本,在这里您将获得以逗号分隔的字符串格式的类属性。
>>> class new_class():
... def __init__(self, number):
... self.multi = int(number)*2
... self.str = str(number)
...
>>> a = new_class(4)
>>> ",".join(a.__dict__.keys())
'str,multi'<br/>
我使用的是python 3.4
其他回答
你可以使用dir(your_object)来获取属性,使用getattr(your_object, your_object_attr)来获取值
用法:
for att in dir(your_object):
print (att, getattr(your_object,att))
如果你的对象没有__dict__,这特别有用。如果不是这样,你也可以尝试var(your_object)
上面所有的答案都是正确的,你有三个选项可以选择
dir () vars () __dict__
>>> dir(a)
['__class__', '__delattr__', '__dict__', '__dir__', '__doc__', '__eq__', '__format__', '__ge__', '__getattribute__', '__gt__', '__hash__', '__init__', '__init_subclass__', '__le__', '__lt__', '__module__', '__ne__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__', '__weakref__', 'multi', 'str']
>>> vars(a)
{'multi': 4, 'str': '2'}
>>> a.__dict__
{'multi': 4, 'str': '2'}
你要这个干什么?如果不知道你的确切意图,可能很难得到最好的答案。
It is almost always better to do this manually if you want to display an instance of your class in a specific way. This will include exactly what you want and not include what you don't want, and the order will be predictable. If you are looking for a way to display the content of a class, manually format the attributes you care about and provide this as the __str__ or __repr__ method for your class. If you want to learn about what methods and such exist for an object to understand how it works, use help. help(a) will show you a formatted output about the object's class based on its docstrings. dir exists for programatically getting all the attributes of an object. (Accessing __dict__ does something I would group as the same but that I wouldn't use myself.) However, this may not include things you want and it may include things you do not want. It is unreliable and people think they want it a lot more often than they do. On a somewhat orthogonal note, there is very little support for Python 3 at the current time. If you are interested in writing real software you are going to want third-party stuff like numpy, lxml, Twisted, PIL, or any number of web frameworks that do not yet support Python 3 and do not have plans to any time too soon. The differences between 2.6 and the 3.x branch are small, but the difference in library support is huge.
获取对象的属性
class new_class():
def __init__(self, number):
self.multi = int(number) * 2
self.str = str(number)
new_object = new_class(2)
print(dir(new_object)) #total list attributes of new_object
attr_value = new_object.__dict__
print(attr_value) #Dictionary of attribute and value for new_class
for attr in attr_value: #attributes on new_class
print(attr)
输出
['__class__', '__delattr__', '__dict__', '__dir__', '__doc__','__eq__', '__format__', '__ge__', '__getattribute__', '__gt__', '__hash__', '__init__', '__init_subclass__', '__le__', '__lt__', '__module__', '__ne__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__', '__weakref__', 'multi', 'str']
{'multi': 4, 'str': '2'}
multi
str
使用__dict__或vars是无效的,因为它会遗漏__slots__。 使用__dict__和__slots__不能工作,因为它从基类中遗漏了__slots__。 使用dir不能工作,因为它包含类属性,如方法或属性,以及对象属性。 使用vars相当于使用__dict__。
这是我最好的:
from typing import Dict
def get_attrs( x : object ) -> Dict[str, object]:
mro = type( x ).mro()
attrs = { }
has_dict = False
sentinel = object()
for klass in mro:
for slot in getattr( klass, "__slots__", () ):
v = getattr( x, slot, sentinel )
if v is sentinel:
continue
if slot == "__dict__":
assert not has_dict, "Multiple __dicts__?"
attrs.update( v )
has_dict = True
else:
attrs[slot] = v
if not has_dict:
attrs.update( getattr( x, "__dict__", { } ) )
return attrs