我需要完成同样的任务，并遇到了这个线程。我最终使用数组“join”使用“_”分隔符创建字符串，然后使用正则表达式：-

1. replace "__" or more with just one "_",
2. replace preceding "_" with nothing "" and similarly 
3. replace and ending "_" with nothing ""

…然后使用数组“拆分”生成一个已清理的数组：-

var myArr = new Array("","","a","b","","c","","","","","","","","","e","");
var myStr = "";

myStr = myArr.join("_");

myStr = myStr.replace(new RegExp(/__*/g),"_");
myStr = myStr.replace(new RegExp(/^_/i),"");
myStr = myStr.replace(new RegExp(/_$/i),"");
myArr = myStr.split("_");

alert("myArr=" + myArr.join(","));

…或1行代码：-

var myArr = new Array("","","a","b","","c","","","","","","","","","e","");

myArr = myArr.join("_").replace(new RegExp(/__*/g),"_").replace(new RegExp(/^_/i),"").replace(new RegExp(/_$/i),"").split("_");

alert("myArr=" + myArr.join(","));

…或，扩展Array对象：-

Array.prototype.clean = function() {
  return this.join("_").replace(new RegExp(/__*/g),"_").replace(new RegExp(/^_/i),"").replace(new RegExp(/_$/i),"").split("_");
};

var myArr = new Array("","","a","b","","c","","","","","","","","","e","");

alert("myArr=" + myArr.clean().join(","));

如果使用库是一个选项，我知道underscore.js有一个名为compact（）的函数http://documentcloud.github.com/underscore/它还有其他几个与数组和集合相关的有用函数。

以下是他们文档的摘录：

_.compact（数组）返回删除了所有错误值的数组副本。在JavaScript中，false、null、0、“”、undefined和NaN都是假的。_.compact（[0，1，false，2，''，3]）；=> [1, 2, 3]

使用正则表达式筛选出无效条目

array = array.filter(/\w/);
filter + regexp

几个简单的方法：

var arr = [1,2,,3,,-3,null,,0,,undefined,4,,4,,5,,6,,,,];

arr.filter(n => n)
// [1, 2, 3, -3, 4, 4, 5, 6]

arr.filter(Number) 
// [1, 2, 3, -3, 4, 4, 5, 6]

arr.filter(Boolean) 
// [1, 2, 3, -3, 4, 4, 5, 6]

或-（仅适用于“text”类型的单个数组项）

['','1','2',3,,'4',,undefined,,,'5'].join('').split(''); 
// output:  ["1","2","3","4","5"]

或-经典方式：简单迭代

var arr = [1,2,null, undefined,3,,3,,,0,,,[],,{},,5,,6,,,,],
    len = arr.length, i;

for(i = 0; i < len; i++ )
    arr[i] && arr.push(arr[i]);  // copy non-empty values to the end of the array

arr.splice(0 , len);  // cut the array and leave only the non-empty values
// [1,2,3,3,[],Object{},5,6]

jQuery：

var arr = [1,2,,3,,3,,,0,,,4,,4,,5,,6,,,,];
    
arr = $.grep(arr, n => n == 0 || n);
// [1, 2, 3, 3, 0, 4, 4, 5, 6]

这可能会帮助您：https://lodash.com/docs/4.17.4#remove

var details = [
            {
                reference: 'ref-1',
                description: 'desc-1',
                price: 1
            }, {
                reference: '',
                description: '',
                price: ''
            }, {
                reference: 'ref-2',
                description: 'desc-2',
                price: 200
            }, {
                reference: 'ref-3',
                description: 'desc-3',
                price: 3
            }, {
                reference: '',
                description: '',
                price: ''
            }
        ];

        scope.removeEmptyDetails(details);
        expect(details.length).toEqual(3);

scope.removeEmptyDetails = function(details){
            _.remove(details, function(detail){
                return (_.isEmpty(detail.reference) && _.isEmpty(detail.description) && _.isEmpty(detail.price));
            });
        };

var a = [{a1: 1, children: [{a1: 2}, undefined, {a1: 3}]}, undefined, {a1: 5}, undefined, {a1: 6}]
function removeNilItemInArray(arr) {
    if (!arr || !arr.length) return;
    for (let i = 0; i < arr.length; i++) {
        if (!arr[i]) {
            arr.splice(i , 1);
            continue;
        }
        removeNilItemInArray(arr[i].children);
    }
}
var b = a;
removeNilItemInArray(a);
// Always keep this memory zone
console.log(b);