我正在使用一个垫子表列出用户选择的语言的内容。他们还可以使用对话框面板添加新的语言。在他们添加了一门语言并返回之后。我希望刷新数据源以显示他们所做的更改。

我通过从服务获取用户数据并在刷新方法中将其传递到数据源来初始化数据存储。

Language.component.ts

import { Component, OnInit } from '@angular/core';
import { LanguageModel, LANGUAGE_DATA } from '../../../../models/language.model';
import { LanguageAddComponent } from './language-add/language-add.component';
import { AuthService } from '../../../../services/auth.service';
import { LanguageDataSource } from './language-data-source';
import { LevelbarComponent } from '../../../../directives/levelbar/levelbar.component';
import { DataSource } from '@angular/cdk/collections';
import { Observable } from 'rxjs/Observable';
import 'rxjs/add/observable/of';
import { MatSnackBar, MatDialog } from '@angular/material';

@Component({
  selector: 'app-language',
  templateUrl: './language.component.html',
  styleUrls: ['./language.component.scss']
})
export class LanguageComponent implements OnInit {

  displayedColumns = ['name', 'native', 'code', 'level'];
  teachDS: any;
  user: any;

  constructor(private authService: AuthService, private dialog: MatDialog) { }

  ngOnInit() {
    this.refresh();
  }

  add() {
    this.dialog.open(LanguageAddComponent, {
      data: { user: this.user },
    }).afterClosed().subscribe(result => {
      this.refresh();
    });
  }

  refresh() {
    this.authService.getAuthenticatedUser().subscribe((res) => {
      this.user = res;
      this.teachDS = new LanguageDataSource(this.user.profile.languages.teach);   
    });
  }
}

language-data-source.ts

import {MatPaginator, MatSort} from '@angular/material';
import {DataSource} from '@angular/cdk/collections';
import {Observable} from 'rxjs/Observable';
import 'rxjs/add/observable/merge';
import 'rxjs/add/operator/map';

export class LanguageDataSource extends DataSource<any> {

  constructor(private languages) {
    super();
  }

  connect(): Observable<any> {
    return Observable.of(this.languages);
  }

  disconnect() {
    // No-op
  }

}

因此,我尝试调用一个刷新方法,我从后端再次获得用户,然后重新初始化数据源。然而,这并没有起作用,没有发生任何变化。


当前回答

好吧,我遇到了一个类似的问题,我向数据源添加了一些东西,但它没有重新加载。

我发现最简单的方法就是重新分配数据

let dataSource = ['a','b','c']
dataSource.push('d')
let cloned = dataSource.slice()
// OR IN ES6 // let cloned = [...dataSource]
dataSource = cloned

其他回答

在Angular 10中,这对我来说是有效的: 在HTML中:

<mat-table [dataSource]="myArray">

在组件TS中:

    myArray: MyObject[] = [];

 addObjectToTable(object:MyObject): void {
      //TO PREVENT DUPLICATED OBJECTS
    if (object&& !this.myArray.includes(object)) {
      this.myArray.push(object);
      // TO FORCE DATA-TABLE's DATASOURCE TO REFRESH
      this.myArray= [...this.myArray];
    }
  }

我利用两种资源获得了一个很好的解决方案:

刷新dataSource和paginator:

this.dataSource.data = this.users;
this.dataSource.connect().next(this.users);
this.paginator._changePageSize(this.paginator.pageSize);

例如,dataSource定义在这里:

    users: User[];
    ...
    dataSource = new MatTableDataSource(this.users);
    ...
    this.dataSource.paginator = this.paginator;
    ...

在我的例子中(Angular 6+),我继承了MatTableDataSource来创建MyDataSource。事后都不打电话。data = someArray

this.entitiesSubject.next(this.data as T[])

未显示的数据

类的一个

export class MyDataSource<T extends WhateverYouWant> extends MatTableDataSource<T> {

    private entitiesSubject = new BehaviorSubject<T[]>([]);


    loadDataSourceData(someArray: T[]){
        this.data = someArray //whenever it comes from an API asyncronously or not
        this.entitiesSubject.next(this.data as T[])// Otherwise data not displayed
    }

    public connect(): BehaviorSubject<T[]> {
        return this.entitiesSubject
    }

}//end Class 

你也可以使用renderRows()方法。

@ViewChild(MatTable, {static: false}) MatTable //初始化

然后 this.table.renderRows ();

作为参考,看看这个: https://www.freakyjolly.com/angular-7-8-edit-add-delete-rows-in-material-table-with-using-dialogs-inline-row-operation/

使用"concat"可以很容易地更新表中的数据:

例如:

language.component.ts

teachDS: any[] = [];

language.component.html

<table mat-table [dataSource]="teachDS" class="list">

并且,当你更新数据(language.component.ts)时:

addItem() {
    // newItem is the object added to the list using a form or other way
    this.teachDS = this.teachDS.concat([newItem]);
 }

当你使用"concat"时,angular检测对象(this.teachDS)的变化,你不需要使用其他东西。

PD:这是我在angular 6和7的工作,我没有尝试其他版本。