在这里你可以找到一个很好的教程(MonoTouch，但你也可以使用非MonoTouch项目的信息): http://redth.info/get-your-monotouch-apps-ready-for-iphone-5-ios-6-today/

为你的splash/default屏幕创建一个新图像(640 x 1136像素)，名称为Default-568h@2x.png 在iOS模拟器中，转到硬件->设备菜单，并选择“iPhone(视网膜4英寸)” 创建其他图像，例如背景图像 检测iPhone 5加载你的新图像:

public static bool IsTall
{
    get {
        return UIDevice.currentDevice.userInterfaceIdiom
                    == UIUserInterfaceIdiomPhone
                && UIScreen.mainScreen.bounds.size.height
                    * UIScreen.mainScreen.scale >= 1136;
    }
}

private static string tallMagic = "-568h@2x";
public static UIImage FromBundle16x9(string path)
{
    //adopt the -568h@2x naming convention
    if(IsTall())
    {
        var imagePath = Path.GetDirectoryName(path.ToString());
        var imageFile = Path.GetFileNameWithoutExtension(path.ToString());
        var imageExt = Path.GetExtension(path.ToString());
        imageFile = imageFile + tallMagic + imageExt;
        return UIImage.FromFile(Path.Combine(imagePath,imageFile));
    }
    else
    {
        return UIImage.FromBundle(path.ToString());
    }
}

要确定你的应用是否支持iPhone 5 Retina，请使用以下方法: (这可以更健壮地返回显示类型，4S视网膜等，但正如下面所写的，如果iPhone支持iOS5视网膜，它只返回YES或NO)

在一个普通的“。h”文件中添加:

BOOL IS_IPHONE5_RETINA(void);

在一个共同的”。M”文件添加:

BOOL IS_IPHONE5_RETINA(void) {
    BOOL isiPhone5Retina = NO;
    if(UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
        if ([UIScreen mainScreen].scale == 2.0f) {
            CGSize result = [[UIScreen mainScreen] bounds].size;
            CGFloat scale = [UIScreen mainScreen].scale;
            result = CGSizeMake(result.width * scale, result.height * scale);

            if(result.height == 960){
                //NSLog(@"iPhone 4, 4s Retina Resolution");
            }
            if(result.height == 1136){
                //NSLog(@"iPhone 5 Resolution");
                isiPhone5Retina = YES;
            }
        } else {
            //NSLog(@"iPhone Standard Resolution");
        }
    }
    return isiPhone5Retina;
}

I never faced such an issue with any device as I've had one codebase for all, without any hardcoded values. What I do is to have the maximum sized image as resource instead of one for each device. For example, I would have one for retina display and show it as aspect fit so it will be views as is on every device. Coming to deciding the frame of button, for instance, at run time. For this I use the % value of the patent view, example , if I want the width to be half of parent view take 50 % of parent and same applies for height and center.

有了这个，我甚至不需要xib。

通过xib .........很容易迁移iPhone5和iPhone4

UIViewController *viewController3;
if ([[UIScreen mainScreen] bounds].size.height == 568)
{
    UIViewController *viewController3 = [[[mainscreenview alloc] initWithNibName:@"iphone5screen" bundle:nil] autorelease];               
}    
else
{
     UIViewController *viewController3 = [[[mainscreenview alloc] initWithNibName:@"iphone4screen" bundle:nil] autorelease];
}

在单例类中尝试下面的方法:

-(NSString *)typeOfDevice
    {
        if(UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
        {
            CGSize result = [[UIScreen mainScreen] bounds].size;
            if(result.height == 480)
            {
                return @"Iphone";
            }
            if(result.height == 568)
            {
                return @"Iphone 5";
            }
        }
        else{
            return @"Ipad";;
        }


        return @"Iphone";
    }

我想，它不是在所有情况下都能工作，但在我的特定项目中，它避免了我对nib文件的重复:

在common.h中，你可以根据屏幕高度来做这些定义:

#define HEIGHT_IPHONE_5 568
#define IS_IPHONE   ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone)
#define IS_IPHONE_5 ([[UIScreen mainScreen] bounds ].size.height == HEIGHT_IPHONE_5)

在你的基本控制器中:

- (void)viewDidLoad
{
    [super viewDidLoad];
    if (IS_IPHONE_5) {
        CGRect r = self.view.frame;
        r.size.height = HEIGHT_IPHONE_5 - 20;
        self.view.frame = r;
    }
    // now the view is stretched properly and not pushed to the bottom
    // it is pushed to the top instead...

    // other code goes here...
}