使用pathlib.Path的解决方案，它独立于所使用的操作系统：

import zipfile
from pathlib import Path

def zip_dir(path: Path, zip_file_path: Path):
    """Zip all contents of path to zip_file"""
    files_to_zip = [
        file for file in path.glob('*') if file.is_file()]
    with zipfile.ZipFile(
        zip_file_path, 'w', zipfile.ZIP_DEFLATED) as zip_f:
        for file in files_to_zip:
            print(file.name)
            zip_f.write(file, file.name)

current_dir = Path.cwd()  
zip_dir = current_dir / "test"
tools.zip_dir(
    zip_dir, current_dir / 'Zipped_dir.zip')

现代Python（3.6+）使用pathlib模块对路径进行类似OOP的简洁处理，使用pathlib.Path.rglob（）进行递归globing。据我所知，这相当于乔治·V·莱利的回答：压缩压缩，最顶层的元素是目录，保持空目录，使用相对路径。

from pathlib import Path
from zipfile import ZIP_DEFLATED, ZipFile

from os import PathLike
from typing import Union


def zip_dir(zip_name: str, source_dir: Union[str, PathLike]):
    src_path = Path(source_dir).expanduser().resolve(strict=True)
    with ZipFile(zip_name, 'w', ZIP_DEFLATED) as zf:
        for file in src_path.rglob('*'):
            zf.write(file, file.relative_to(src_path.parent))

注意：如可选类型提示所示，zip_name不能是Path对象（将在3.6.2+中修复）。

正如其他人所指出的，您应该使用zipfile。文档告诉哪些函数可用，但并没有真正解释如何使用它们压缩整个目录。我认为用一些示例代码来解释是最简单的：

import os
import zipfile
    
def zipdir(path, ziph):
    # ziph is zipfile handle
    for root, dirs, files in os.walk(path):
        for file in files:
            ziph.write(os.path.join(root, file), 
                       os.path.relpath(os.path.join(root, file), 
                                       os.path.join(path, '..')))

with zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED) as zipf:
    zipdir('tmp/', zipf)

# import required python modules
# You have to install zipfile package using pip install

import os,zipfile

# Change the directory where you want your new zip file to be

os.chdir('Type your destination')

# Create a new zipfile ( I called it myfile )

zf = zipfile.ZipFile('myfile.zip','w')

# os.walk gives a directory tree. Access the files using a for loop

for dirnames,folders,files in os.walk('Type your directory'):
    zf.write('Type your Directory')
    for file in files:
        zf.write(os.path.join('Type your directory',file))

要向生成的zip文件添加压缩，请查看此链接。

您需要更改：

zip = zipfile.ZipFile('Python.zip', 'w')

to

zip = zipfile.ZipFile('Python.zip', 'w', zipfile.ZIP_DEFLATED)

前面的答案完全忽略了一点，即当您在Windows上运行代码时，使用os.path.join（）可以很容易地返回POSIX不兼容的路径。当使用Linux上的任何常用归档软件处理文件时，生成的归档文件将包含名称中带有反斜杠的文件，这不是您想要的。请改用path.as_posix（）作为arcname参数！

import zipfile
from pathlib import Path
with zipfile.ZipFile("archive.zip", "w", zipfile.ZIP_DEFLATED) as zf:
    for path in Path("include_all_of_this_folder").rglob("*"):
        zf.write(path, path.as_posix())