是否有一个快速和简单的方法来编码JavaScript对象到字符串,我可以通过GET请求传递?

没有jQuery,没有其他框架-只有纯JavaScript:)


当前回答

PHP符号的TypeScript版本(没有URL转义版本)

/**
 * Converts an object into a Cookie-like string.
 * @param toSerialize object or array to be serialized
 * @param prefix used in deep objects to describe the final query parameter
 * @returns ampersand separated key=value pairs
 *
 * Example:
 * ```js
 * serialize({hello:[{world: "nice"}]}); // outputs  "hello[0][world]=nice"
 * ```
 * ---
 * Adapted to TS from a StackOverflow answer https://stackoverflow.com/a/1714899/4537906
 */
const serialize = (toSerialize: unknown = {}, prefix?: string) => {
  const keyValuePairs = [];

  Object.keys(toSerialize).forEach((attribute) => {
    if (Object.prototype.hasOwnProperty.call(toSerialize, attribute)) {
      const key = prefix ? `${prefix}[${attribute}]` : attribute;
      const value = toSerialize[attribute];
      const toBePushed =
        value !== null && typeof value === "object"
          ? serialize(value, key)
          : `${key}=${value}`;
      keyValuePairs.push(toBePushed);
    }
  });

  return keyValuePairs.join("&");
};

其他回答

在ES7中,你可以用一行写:

const serialize = (obj) => (Object.entries(obj).map(i => [i[0], encodeURIComponent(i[1])].join('=')).join('&'))

如果您需要发送任意对象,那么GET是一个坏主意,因为有限制的url长度,用户代理和web服务器将接受。我的建议是建立一个名称-值对数组来发送,然后建立一个查询字符串:

function QueryStringBuilder() {
    var nameValues = [];

    this.add = function(name, value) {
        nameValues.push( {name: name, value: value} );
    };

    this.toQueryString = function() {
        var segments = [], nameValue;
        for (var i = 0, len = nameValues.length; i < len; i++) {
            nameValue = nameValues[i];
            segments[i] = encodeURIComponent(nameValue.name) + "=" + encodeURIComponent(nameValue.value);
        }
        return segments.join("&");
    };
}

var qsb = new QueryStringBuilder();
qsb.add("veg", "cabbage");
qsb.add("vegCount", "5");

alert( qsb.toQueryString() );

URLSearchParams看起来不错,但是对于嵌套对象来说行不通。

试着使用

encodeURIComponent(JSON.stringify(object))

下面是Object.entries的简洁递归版本。它处理任意嵌套的数组,但不处理嵌套的对象。它还会删除空元素:

const format = (k,v) => v !== null ? `${k}=${encodeURIComponent(v)}` : ''

const to_qs = (obj) => {
    return [].concat(...Object.entries(obj)
                       .map(([k,v]) => Array.isArray(v) 
                          ? v.map(arr => to_qs({[k]:arr})) 
                          : format(k,v)))
           .filter(x => x)
           .join('&');
}

例如:

let json = { 
    a: [1, 2, 3],
    b: [],              // omit b
    c: 1,
    d: "test&encoding", // uriencode
    e: [[4,5],[6,7]],   // flatten this
    f: null,            // omit nulls
    g: 0
};

let qs = to_qs(json)

=> "a=1&a=2&a=3&c=1&d=test%26encoding&e=4&e=5&e=6&e=7&g=0"

参考答案@user187291,添加“isArray”作为参数,使要转换的JSON嵌套数组。

data : {
                    staffId : "00000001",
                    Detail : [ {
                        "identityId" : "123456"
                    }, {
                        "identityId" : "654321"
                    } ],

                }

要得到结果:

staffId=00000001&Detail[0].identityId=123456&Detail[1].identityId=654321

serialize = function(obj, prefix, isArray) {
        var str = [],p = 0;
        for (p in obj) {
            if (obj.hasOwnProperty(p)) {
                var k, v;
                if (isArray)
                    k = prefix ? prefix + "[" + p + "]" : p, v = obj[p];
                else
                    k = prefix ? prefix + "." + p + "" : p, v = obj[p];

                if (v !== null && typeof v === "object") {
                    if (Array.isArray(v)) {
                        serialize(v, k, true);
                    } else {
                        serialize(v, k, false);
                    }
                } else {
                    var query = k + "=" + v;
                    str.push(query);
                }
            }
        }
        return str.join("&");
    };

    serialize(data, "prefix", false);