参考答案@user187291，添加“isArray”作为参数，使要转换的JSON嵌套数组。

data : {
                    staffId : "00000001",
                    Detail : [ {
                        "identityId" : "123456"
                    }, {
                        "identityId" : "654321"
                    } ],

                }

要得到结果:

staffId=00000001&Detail[0].identityId=123456&Detail[1].identityId=654321

serialize = function(obj, prefix, isArray) {
        var str = [],p = 0;
        for (p in obj) {
            if (obj.hasOwnProperty(p)) {
                var k, v;
                if (isArray)
                    k = prefix ? prefix + "[" + p + "]" : p, v = obj[p];
                else
                    k = prefix ? prefix + "." + p + "" : p, v = obj[p];

                if (v !== null && typeof v === "object") {
                    if (Array.isArray(v)) {
                        serialize(v, k, true);
                    } else {
                        serialize(v, k, false);
                    }
                } else {
                    var query = k + "=" + v;
                    str.push(query);
                }
            }
        }
        return str.join("&");
    };

    serialize(data, "prefix", false);

好吧，这是一个旧的帖子，但我正面临这个问题，我已经找到了我的个人解决方案。也许可以帮助别人…

     function objToQueryString(obj){
        var k = Object.keys(obj);
        var s = "";
        for(var i=0;i<k.length;i++) {
            s += k[i] + "=" + encodeURIComponent(obj[k[i]]);
            if (i != k.length -1) s += "&";
        }
        return s;
     };

 let data = {
    id:1,
    name:'Newuser'
    };
const getqueryParam = data => {
  let datasize = Object.keys(data).length;
  let initial = '?';

  Object.keys(data).map(function (key, index) {
    initial = initial.concat(`${key}=${data[key]}`);
    index != datasize - 1 && (initial = initial.concat('&'));
  });
  console.log(initial, 'MyqueryString');
  return initial;
};

console.log(getqueryParam(data))//You can get the query string here

If you have baseUrl means to get full query use 

baseUrl concat (getqueryParam(数据)。

在ES7中，你可以用一行写:

const serialize = (obj) => (Object.entries(obj).map(i => [i[0], encodeURIComponent(i[1])].join('=')).join('&'))

如果有很多嵌套对象，前面的答案就不起作用了。

相反，你可以从jquery-param/jquery-param.js中选择函数参数。这对我来说非常有效!

    var param = function (a) {
    var s = [], rbracket = /\[\]$/,
        isArray = function (obj) {
            return Object.prototype.toString.call(obj) === '[object Array]';
        }, add = function (k, v) {
            v = typeof v === 'function' ? v() : v === null ? '' : v === undefined ? '' : v;
            s[s.length] = encodeURIComponent(k) + '=' + encodeURIComponent(v);
        }, buildParams = function (prefix, obj) {
            var i, len, key;

            if (prefix) {
                if (isArray(obj)) {
                    for (i = 0, len = obj.length; i < len; i++) {
                        if (rbracket.test(prefix)) {
                            add(prefix, obj[i]);
                        } else {
                            buildParams(prefix + '[' + (typeof obj[i] === 'object' ? i : '') + ']', obj[i]);
                        }
                    }
                } else if (obj && String(obj) === '[object Object]') {
                    for (key in obj) {
                        buildParams(prefix + '[' + key + ']', obj[key]);
                    }
                } else {
                    add(prefix, obj);
                }
            } else if (isArray(obj)) {
                for (i = 0, len = obj.length; i < len; i++) {
                    add(obj[i].name, obj[i].value);
                }
            } else {
                for (key in obj) {
                    buildParams(key, obj[key]);
                }
            }
            return s;
        };

    return buildParams('', a).join('&').replace(/%20/g, '+');
};

Ramda:

    R.pipe(R.toPairs, R.map(R.join('=')), R.join('&'))({a: 'b', b: 'a'})