这是我用的。它结合了进程枚举来执行切换和互斥，以防止“活动点击器”:

public partial class App
{
    [DllImport("user32")]
    private static extern int OpenIcon(IntPtr hWnd);

    [DllImport("user32.dll")]
    private static extern bool SetForegroundWindow(IntPtr hWnd);

    protected override void OnStartup(StartupEventArgs e)
    {
        base.OnStartup(e);
        var p = Process
           .GetProcessesByName(Process.GetCurrentProcess().ProcessName);
            foreach (var t in p.Where(t => t.MainWindowHandle != IntPtr.Zero))
            {
                OpenIcon(t.MainWindowHandle);
                SetForegroundWindow(t.MainWindowHandle);
                Current.Shutdown();
                return;
            }

            // there is a chance the user tries to click on the icon repeatedly
            // and the process cannot be discovered yet
            bool createdNew;
            var mutex = new Mutex(true, "MyAwesomeApp", 
               out createdNew);  // must be a variable, though it is unused - 
            // we just need a bit of time until the process shows up
            if (!createdNew)
            {
                Current.Shutdown();
                return;
            }

            new Bootstrapper().Run();
        }
    }

我在解决方案中使用互斥来防止多个实例。

static Mutex mutex = null;
//A string that is the name of the mutex
string mutexName = @"Global\test";
//Prevent Multiple Instances of Application
bool onlyInstance = false;
mutex = new Mutex(true, mutexName, out onlyInstance);

if (!onlyInstance)
{
  MessageBox.Show("You are already running this application in your system.", "Already Running..", MessageBoxButton.OK);
  Application.Current.Shutdown();
}

我在这里找不到一个简单的解决方案，所以我希望有人会喜欢这个:

更新2018-09-20

把这段代码放在Program.cs中:

using System.Diagnostics;

static void Main()
{
    Process thisProcess = Process.GetCurrentProcess();
    Process[] allProcesses = Process.GetProcessesByName(thisProcess.ProcessName);
    if (allProcesses.Length > 1)
    {
        // Don't put a MessageBox in here because the user could spam this MessageBox.
        return;
    }

    // Optional code. If you don't want that someone runs your ".exe" with a different name:

    string exeName = AppDomain.CurrentDomain.FriendlyName;
    // in debug mode, don't forget that you don't use your normal .exe name.
    // Debug uses the .vshost.exe.
    if (exeName != "the name of your executable.exe") 
    {
        // You can add a MessageBox here if you want.
        // To point out to users that the name got changed and maybe what the name should be or something like that^^ 
        MessageBox.Show("The executable name should be \"the name of your executable.exe\"", 
            "Wrong executable name", MessageBoxButtons.OK, MessageBoxIcon.Error);
        return;
    }

    // Following code is default code:
    Application.EnableVisualStyles();
    Application.SetCompatibleTextRenderingDefault(false);
    Application.Run(new MainForm());
}

这就是我最终处理这个问题的方式。注意，调试代码仍然在那里进行测试。这段代码在App.xaml.cs文件的OnStartup中。(WPF)

        // Process already running ? 
        if (Process.GetProcessesByName(Process.GetCurrentProcess().ProcessName).Length > 1)
        {

            // Show your error message
            MessageBox.Show("xxx is already running.  \r\n\r\nIf the original process is hung up you may need to restart your computer, or kill the current xxx process using the task manager.", "xxx is already running!", MessageBoxButton.OK, MessageBoxImage.Exclamation);

            // This process 
            Process currentProcess = Process.GetCurrentProcess();

            // Get all processes running on the local computer.
            Process[] localAll = Process.GetProcessesByName(Process.GetCurrentProcess().ProcessName);

            // ID of this process... 
            int temp = currentProcess.Id;
            MessageBox.Show("This Process ID:  " + temp.ToString());

            for (int i = 0; i < localAll.Length; i++)
            {
                // Find the other process 
                if (localAll[i].Id != currentProcess.Id)
                {
                    MessageBox.Show("Original Process ID (Switching to):  " + localAll[i].Id.ToString());

                    // Switch to it... 
                    SetForegroundWindow(localAll[i].MainWindowHandle);

                }
            }

            Application.Current.Shutdown();

        }

这可能有我还没有发现的问题。如果我遇到了，我会更新我的答案。

我喜欢一个解决方案，以允许多个实例，如果exe是从其他路径调用。我修改了CharithJ溶液方法一:

   static class Program {
    [DllImport("user32.dll")]
    private static extern bool ShowWindow(IntPtr hWnd, Int32 nCmdShow);
    [DllImport("User32.dll")]
    public static extern Int32 SetForegroundWindow(IntPtr hWnd);
    [STAThread]
    static void Main() {
        Process currentProcess = Process.GetCurrentProcess();
        foreach (var process in Process.GetProcesses()) {
            try {
                if ((process.Id != currentProcess.Id) && 
                    (process.ProcessName == currentProcess.ProcessName) &&
                    (process.MainModule.FileName == currentProcess.MainModule.FileName)) {
                    ShowWindow(process.MainWindowHandle, 5); // const int SW_SHOW = 5; //Activates the window and displays it in its current size and position. 
                    SetForegroundWindow(process.MainWindowHandle);
                    return;
                }
            } catch (Exception ex) {
                //ignore Exception "Access denied "
            }
        }

        Application.EnableVisualStyles();
        Application.SetCompatibleTextRenderingDefault(false);
        Application.Run(new Form1());
    }
}

这是我的整个App.xaml.cs，这段代码也将启动的程序实例带到前台:

public partial class App : Application
{
    private static Mutex _mutex = null;

    [DllImport("user32.dll")]
    static extern bool SetForegroundWindow(IntPtr hWnd);

    [DllImport("user32.dll")]
    static extern bool ShowWindow(IntPtr hWnd, int nCmdShow);

    protected override void OnStartup(StartupEventArgs e)
    {
        _mutex = new Mutex(true, "YourMutexName", out var createdNew);

        if (!createdNew)
        {
            using (var currentProcess = Process.GetCurrentProcess())
            {
                foreach (var process in Process.GetProcessesByName(currentProcess.ProcessName))
                {
                    if (process.Id != currentProcess.Id)
                    {
                        ShowWindow(process.MainWindowHandle, 9);
                        SetForegroundWindow(process.MainWindowHandle);
                    }
                    process.Dispose();
                }
            }
            // app is already running! Exiting the application  
            Shutdown();
        }

        base.OnStartup(e);
    }

    protected override void OnExit(ExitEventArgs e)
    {
        _mutex.Dispose();
        base.OnExit(e);
    }
}