我如何在另一个JavaScript文件中添加一个JavaScript文件,类似于CSS中的 @import?


当前回答

我写了一个简单的模块,它自动化了在JavaScript中进口/包含模块脚本的工作。 详细解释代码,请参阅博客帖子JavaScript需要/进口/包含模块。

// ----- USAGE -----

require('ivar.util.string');
require('ivar.net.*');
require('ivar/util/array.js');
require('http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js');

ready(function(){
    //Do something when required scripts are loaded
});

    //--------------------

var _rmod = _rmod || {}; //Require module namespace
_rmod.LOADED = false;
_rmod.on_ready_fn_stack = [];
_rmod.libpath = '';
_rmod.imported = {};
_rmod.loading = {
    scripts: {},
    length: 0
};

_rmod.findScriptPath = function(script_name) {
    var script_elems = document.getElementsByTagName('script');
    for (var i = 0; i < script_elems.length; i++) {
        if (script_elems[i].src.endsWith(script_name)) {
            var href = window.location.href;
            href = href.substring(0, href.lastIndexOf('/'));
            var url = script_elems[i].src.substring(0, script_elems[i].length - script_name.length);
            return url.substring(href.length+1, url.length);
        }
    }
    return '';
};

_rmod.libpath = _rmod.findScriptPath('script.js'); //Path of your main script used to mark
                                                   //the root directory of your library, any library.


_rmod.injectScript = function(script_name, uri, callback, prepare) {

    if(!prepare)
        prepare(script_name, uri);

    var script_elem = document.createElement('script');
    script_elem.type = 'text/javascript';
    script_elem.title = script_name;
    script_elem.src = uri;
    script_elem.async = true;
    script_elem.defer = false;

    if(!callback)
        script_elem.onload = function() {
            callback(script_name, uri);
        };
    document.getElementsByTagName('head')[0].appendChild(script_elem);
};

_rmod.requirePrepare = function(script_name, uri) {
    _rmod.loading.scripts[script_name] = uri;
    _rmod.loading.length++;
};

_rmod.requireCallback = function(script_name, uri) {
    _rmod.loading.length--;
    delete _rmod.loading.scripts[script_name];
    _rmod.imported[script_name] = uri;

    if(_rmod.loading.length == 0)
        _rmod.onReady();
};

_rmod.onReady = function() {
    if (!_rmod.LOADED) {
        for (var i = 0; i < _rmod.on_ready_fn_stack.length; i++){
            _rmod.on_ready_fn_stack[i]();
        });
        _rmod.LOADED = true;
    }
};

_.rmod = namespaceToUri = function(script_name, url) {
    var np = script_name.split('.');
    if (np.getLast() === '*') {
        np.pop();
        np.push('_all');
    }

    if(!url)
        url = '';

    script_name = np.join('.');
    return  url + np.join('/')+'.js';
};

//You can rename based on your liking. I chose require, but it
//can be called include or anything else that is easy for you
//to remember or write, except "import", because it is reserved
//for future use.
var require = function(script_name) {
    var uri = '';
    if (script_name.indexOf('/') > -1) {
        uri = script_name;
        var lastSlash = uri.lastIndexOf('/');
        script_name = uri.substring(lastSlash+1, uri.length);
    } 
    else {
        uri = _rmod.namespaceToUri(script_name, ivar._private.libpath);
    }

    if (!_rmod.loading.scripts.hasOwnProperty(script_name)
     && !_rmod.imported.hasOwnProperty(script_name)) {
        _rmod.injectScript(script_name, uri,
            _rmod.requireCallback,
                _rmod.requirePrepare);
    }
};

var ready = function(fn) {
    _rmod.on_ready_fn_stack.push(fn);
};

其他回答

我基本上做如下,创建一个新的元素,并添加它来主导:

var x = document.createElement('script');
x.src = 'http://example.com/test.js';
document.getElementsByTagName("head")[0].appendChild(x);

在 jQuery 中:

// jQuery
$.getScript('/path/to/imported/script.js', function()
{
    // Script is now loaded and executed.
    // Put your dependent JavaScript code here.
});

另一个方法是使用HTML进口,这些可以包含脚本参考以及风格表参考。

您可以将 HTML 文件链接到

<link rel="import" href="vendorScripts.html"/>

在 vendorScripts.html 文件中,您可以包含您的脚本参考,如:

<script src="scripts/vendors/jquery.js"></script>
<script src="scripts/vendors/bootstrap.js"></script>
<script src="scripts/vendors/angular.js"></script>
<script src="scripts/vendors/angular-route.js"></script>

查看 HTML Imports 更多详细信息。

不幸的是,它只在Chrome中工作。

我有要求无同步加载一系列的JavaScript文件,最终进行呼叫回复。

// Load a JavaScript file from other JavaScript file
function loadScript(urlPack, callback) {
    var url = urlPack.shift();
    var subCallback;

    if (urlPack.length == 0) subCallback = callback;
    else subCallback = function () {
        console.log("Log script: " + new Date().getTime());
        loadScript(urlPack, callback);
    }

    // Adding the script tag to the head as suggested before
    var head = document.getElementsByTagName('head')[0];
    var script = document.createElement('script');
    script.type = 'text/javascript';
    script.src = url;

    // Then bind the event to the callback function.
    // There are several events for cross browser compatibility.
    script.onreadystatechange = subCallback;
    script.onload = subCallback;

    // Fire the loading
    head.appendChild(script);
}

例子:

loadScript(
[
    "js/DataTable/jquery.dataTables.js",
    "js/DataTable/dataTables.bootstrap.js",
    "js/DataTable/dataTables.buttons.min.js",
    "js/DataTable/dataTables.colReorder.min.js",
    "js/DataTable/dataTables.fixedHeader.min.js",
    "js/DataTable/buttons.bootstrap.min.js",
    "js/DataTable/buttons.colVis.min.js",
    "js/DataTable/buttons.html5.min.js"
], function() { gpLoad(params); });

第二个脚本不会充电,直到第一个完全充电,因此...

结果:

此分類上一篇

在现代语言中,如果脚本已经加载了,则会:

function loadJs( url ){
  return new Promise(( resolve, reject ) => {
    if (document.querySelector( `head > script[ src = "${url}" ]`) !== null ){
        console.warn( `script already loaded: ${url}` );
        resolve();
    }
    const script = document.createElement( "script" );
    script.src = url;
    script.onload = resolve;
    script.onerror = function( reason ){
        // This can be useful for your error-handling code
        reason.message = `error trying to load script ${url}`;
        reject( reason );
    };
    document.head.appendChild( script );
  });
}

使用(async/await):

try { await loadJs("https://.../script.js"); }
catch(error) { console.log(error); }

await loadJs( "https://.../script.js" ).catch( err => {} );

使用(承诺):

loadJs( "https://.../script.js" ).then( res => {} ).catch( err => {} );

如果你发现有两个或多个脚本在被召唤时占据相同功能,我们不能同时包含它们,我们需要通过用户选择进行动态操作。

在 jQuery 中的另一个文件使用 $.getScript 工作,因为脚本不会默认隐藏。

HTML

<select class="choice">
  <option value="script1" selected>Script-1</option>
  <option value="script2">Script-2</option>
</select>

雅各布斯

$(".choice").change(on_change);

var url = "https://example.com";
$.url1 = url + "/script1.js";
$.url2 = url + "/script2.js";

function on_change() {
  if ($(".choice").val()=="script1") {
    script1();
  } else {
    script2();
  }
}

// script1
function script1() {
  $.getScript($.url1, function( data, textStatus, jqxhr ) {
    // Execute here
  });
}

// script2
function script2() {
  $.getScript($.url2, function( data, textStatus, jqxhr ) {
    // Execute here
  });
}