假设我有一个字符串:
string str = "1111222233334444";
我如何把这个字符串分成一定大小的块?
例如,将它分解为4的大小将返回字符串:
"1111"
"2222"
"3333"
"4444"
假设我有一个字符串:
string str = "1111222233334444";
我如何把这个字符串分成一定大小的块?
例如,将它分解为4的大小将返回字符串:
"1111"
"2222"
"3333"
"4444"
当前回答
List<string> SplitString(int chunk, string input)
{
List<string> list = new List<string>();
int cycles = input.Length / chunk;
if (input.Length % chunk != 0)
cycles++;
for (int i = 0; i < cycles; i++)
{
try
{
list.Add(input.Substring(i * chunk, chunk));
}
catch
{
list.Add(input.Substring(i * chunk));
}
}
return list;
}
其他回答
根据其他帖子的答案,以及一些使用示例:
public static string FormatSortCode(string sortCode)
{
return ChunkString(sortCode, 2, "-");
}
public static string FormatIBAN(string iban)
{
return ChunkString(iban, 4, " ");
}
private static string ChunkString(string str, int chunkSize, string separator)
{
var b = new StringBuilder();
var stringLength = str.Length;
for (var i = 0; i < stringLength; i += chunkSize)
{
if (i + chunkSize > stringLength) chunkSize = stringLength - i;
b.Append(str.Substring(i, chunkSize));
if (i+chunkSize != stringLength)
b.Append(separator);
}
return b.ToString();
}
这也可以用这种方式来完成
string actualString = "1111222233334444";
var listResult = new List<string>();
int groupingLength = actualString.Length % 4;
if (groupingLength > 0)
listResult.Add(actualString.Substring(0, groupingLength));
for (int i = groupingLength; i < actualString.Length; i += 4)
{
listResult.Add(actualString.Substring(i, 4));
}
foreach(var res in listResult)
{
Console.WriteLine(res);
}
Console.Read();
List<string> SplitString(int chunk, string input)
{
List<string> list = new List<string>();
int cycles = input.Length / chunk;
if (input.Length % chunk != 0)
cycles++;
for (int i = 0; i < cycles; i++)
{
try
{
list.Add(input.Substring(i * chunk, chunk));
}
catch
{
list.Add(input.Substring(i * chunk));
}
}
return list;
}
试试这个:
public static string[] Split(string str, int chunkSize)
{
return Enumerable.Range(0, str.Length / chunkSize)
.Select(i => str.Substring(i * chunkSize, chunkSize)).ToArray();
}
它基于@dove解决方案,但作为扩展方法实现。
好处:
扩展方法 涵盖角落案例 分割字符串与任何字符:数字,字母,其他符号
Code
public static class EnumerableEx
{
public static IEnumerable<string> SplitBy(this string str, int chunkLength)
{
if (String.IsNullOrEmpty(str)) throw new ArgumentException();
if (chunkLength < 1) throw new ArgumentException();
for (int i = 0; i < str.Length; i += chunkLength)
{
if (chunkLength + i > str.Length)
chunkLength = str.Length - i;
yield return str.Substring(i, chunkLength);
}
}
}
使用
var result = "bobjoecat".SplitBy(3); // bob, joe, cat
为简洁起见,删除了单元测试(请参阅以前的修订版)