假设我有一个字符串:

string str = "1111222233334444"; 

我如何把这个字符串分成一定大小的块?

例如,将它分解为4的大小将返回字符串:

"1111"
"2222"
"3333"
"4444"

当前回答

根据其他帖子的答案,以及一些使用示例:

public static string FormatSortCode(string sortCode)
{
    return ChunkString(sortCode, 2, "-");
}
public static string FormatIBAN(string iban)
{
    return ChunkString(iban, 4, "  ");
}

private static string ChunkString(string str, int chunkSize, string separator)
{
    var b = new StringBuilder();
    var stringLength = str.Length;
    for (var i = 0; i < stringLength; i += chunkSize)
    {
        if (i + chunkSize > stringLength) chunkSize = stringLength - i;
        b.Append(str.Substring(i, chunkSize));
        if (i+chunkSize != stringLength)
            b.Append(separator);
    }
    return b.ToString();
}

其他回答

使用IX库中的Buffer扩展

    static IEnumerable<string> Split( this string str, int chunkSize )
    {
        return str.Buffer(chunkSize).Select(l => String.Concat(l));
    }

我不记得是谁给我的了,但它很好用。我快速测试了几种将枚举类型分成组的方法。用法是这样的…

List<string> Divided = Source3.Chunk(24).Select(Piece => string.Concat<char>(Piece)).ToList();

扩展代码看起来像这样…

#region Chunk Logic
private class ChunkedEnumerable<T> : IEnumerable<T>
{
    class ChildEnumerator : IEnumerator<T>
    {
        ChunkedEnumerable<T> parent;
        int position;
        bool done = false;
        T current;


        public ChildEnumerator(ChunkedEnumerable<T> parent)
        {
            this.parent = parent;
            position = -1;
            parent.wrapper.AddRef();
        }

        public T Current
        {
            get
            {
                if (position == -1 || done)
                {
                    throw new InvalidOperationException();
                }
                return current;

            }
        }

        public void Dispose()
        {
            if (!done)
            {
                done = true;
                parent.wrapper.RemoveRef();
            }
        }

        object System.Collections.IEnumerator.Current
        {
            get { return Current; }
        }

        public bool MoveNext()
        {
            position++;

            if (position + 1 > parent.chunkSize)
            {
                done = true;
            }

            if (!done)
            {
                done = !parent.wrapper.Get(position + parent.start, out current);
            }

            return !done;

        }

        public void Reset()
        {
            // per http://msdn.microsoft.com/en-us/library/system.collections.ienumerator.reset.aspx
            throw new NotSupportedException();
        }
    }

    EnumeratorWrapper<T> wrapper;
    int chunkSize;
    int start;

    public ChunkedEnumerable(EnumeratorWrapper<T> wrapper, int chunkSize, int start)
    {
        this.wrapper = wrapper;
        this.chunkSize = chunkSize;
        this.start = start;
    }

    public IEnumerator<T> GetEnumerator()
    {
        return new ChildEnumerator(this);
    }

    System.Collections.IEnumerator System.Collections.IEnumerable.GetEnumerator()
    {
        return GetEnumerator();
    }

}
private class EnumeratorWrapper<T>
{
    public EnumeratorWrapper(IEnumerable<T> source)
    {
        SourceEumerable = source;
    }
    IEnumerable<T> SourceEumerable { get; set; }

    Enumeration currentEnumeration;

    class Enumeration
    {
        public IEnumerator<T> Source { get; set; }
        public int Position { get; set; }
        public bool AtEnd { get; set; }
    }

    public bool Get(int pos, out T item)
    {

        if (currentEnumeration != null && currentEnumeration.Position > pos)
        {
            currentEnumeration.Source.Dispose();
            currentEnumeration = null;
        }

        if (currentEnumeration == null)
        {
            currentEnumeration = new Enumeration { Position = -1, Source = SourceEumerable.GetEnumerator(), AtEnd = false };
        }

        item = default(T);
        if (currentEnumeration.AtEnd)
        {
            return false;
        }

        while (currentEnumeration.Position < pos)
        {
            currentEnumeration.AtEnd = !currentEnumeration.Source.MoveNext();
            currentEnumeration.Position++;

            if (currentEnumeration.AtEnd)
            {
                return false;
            }

        }

        item = currentEnumeration.Source.Current;

        return true;
    }

    int refs = 0;

    // needed for dispose semantics 
    public void AddRef()
    {
        refs++;
    }

    public void RemoveRef()
    {
        refs--;
        if (refs == 0 && currentEnumeration != null)
        {
            var copy = currentEnumeration;
            currentEnumeration = null;
            copy.Source.Dispose();
        }
    }
}
/// <summary>Speed Checked.  Works Great!</summary>
public static IEnumerable<IEnumerable<T>> Chunk<T>(this IEnumerable<T> source, int chunksize)
{
    if (chunksize < 1) throw new InvalidOperationException();

    var wrapper = new EnumeratorWrapper<T>(source);

    int currentPos = 0;
    T ignore;
    try
    {
        wrapper.AddRef();
        while (wrapper.Get(currentPos, out ignore))
        {
            yield return new ChunkedEnumerable<T>(wrapper, chunksize, currentPos);
            currentPos += chunksize;
        }
    }
    finally
    {
        wrapper.RemoveRef();
    }
}
#endregion

这也可以用这种方式来完成

        string actualString = "1111222233334444";
        var listResult = new List<string>();
        int groupingLength = actualString.Length % 4;
        if (groupingLength > 0)
            listResult.Add(actualString.Substring(0, groupingLength));
        for (int i = groupingLength; i < actualString.Length; i += 4)
        {
            listResult.Add(actualString.Substring(i, 4));
        }

        foreach(var res in listResult)
        {
            Console.WriteLine(res);
        }
        Console.Read();

最好,最简单和一般的答案:)。

    string originalString = "1111222233334444";
    List<string> test = new List<string>();
    int chunkSize = 4; // change 4 with the size of strings you want.
    for (int i = 0; i < originalString.Length; i = i + chunkSize)
    {
        if (originalString.Length - i >= chunkSize)
            test.Add(originalString.Substring(i, chunkSize));
        else
            test.Add(originalString.Substring(i,((originalString.Length - i))));
    }

为什么不是循环?这里有一些东西可以很好地做到这一点:

        string str = "111122223333444455";
        int chunkSize = 4;
        int stringLength = str.Length;
        for (int i = 0; i < stringLength ; i += chunkSize)
        {
            if (i + chunkSize > stringLength) chunkSize = stringLength  - i;
            Console.WriteLine(str.Substring(i, chunkSize));

        }
        Console.ReadLine();

我不知道你会如何处理字符串不是因子4的情况,但不是说你的想法是不可能的,只是想知道它的动机,如果一个简单的for循环做得很好?显然,上面的内容可以被清除,甚至可以作为扩展方法加入。

或者正如评论中提到的,你知道它是/4

str = "1111222233334444";
for (int i = 0; i < stringLength; i += chunkSize) 
  {Console.WriteLine(str.Substring(i, chunkSize));}