我发现了一个与PHP中的函数相当的JS范围函数，在这里工作得非常棒。向前和向后工作，可以处理整数、浮点数和字母！

function range(low, high, step) {
  //  discuss at: http://phpjs.org/functions/range/
  // original by: Waldo Malqui Silva
  //   example 1: range ( 0, 12 );
  //   returns 1: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]
  //   example 2: range( 0, 100, 10 );
  //   returns 2: [0, 10, 20, 30, 40, 50, 60, 70, 80, 90, 100]
  //   example 3: range( 'a', 'i' );
  //   returns 3: ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i']
  //   example 4: range( 'c', 'a' );
  //   returns 4: ['c', 'b', 'a']

  var matrix = [];
  var inival, endval, plus;
  var walker = step || 1;
  var chars = false;

  if (!isNaN(low) && !isNaN(high)) {
    inival = low;
    endval = high;
  } else if (isNaN(low) && isNaN(high)) {
    chars = true;
    inival = low.charCodeAt(0);
    endval = high.charCodeAt(0);
  } else {
    inival = (isNaN(low) ? 0 : low);
    endval = (isNaN(high) ? 0 : high);
  }

  plus = ((inival > endval) ? false : true);
  if (plus) {
    while (inival <= endval) {
      matrix.push(((chars) ? String.fromCharCode(inival) : inival));
      inival += walker;
    }
  } else {
    while (inival >= endval) {
      matrix.push(((chars) ? String.fromCharCode(inival) : inival));
      inival -= walker;
    }
  }

  return matrix;
}

这是缩小版：

function range(h,c,b){var i=[];var d,f,e;var a=b||1;var g=false;if(!isNaN(h)&&!isNaN(c)){d=h;f=c}else{if(isNaN(h)&&isNaN(c)){g=true;d=h.charCodeAt(0);f=c.charCodeAt(0)}else{d=(isNaN(h)?0:h);f=(isNaN(c)?0:c)}}e=((d>f)?false:true);if(e){while(d<=f){i.push(((g)?String.fromCharCode(d):d));d+=a}}else{while(d>=f){i.push(((g)?String.fromCharCode(d):d));d-=a}}return i};

数字

[...Array(5).keys()];
 => [0, 1, 2, 3, 4]

字符迭代

String.fromCharCode(...[...Array('D'.charCodeAt(0) - 'A'.charCodeAt(0) + 1).keys()].map(i => i + 'A'.charCodeAt(0)));
 => "ABCD"

迭代

for (const x of Array(5).keys()) {
  console.log(x, String.fromCharCode('A'.charCodeAt(0) + x));
}
 => 0,"A" 1,"B" 2,"C" 3,"D" 4,"E"

作为函数

function range(size, startAt = 0) {
    return [...Array(size).keys()].map(i => i + startAt);
}

function characterRange(startChar, endChar) {
    return String.fromCharCode(...range(endChar.charCodeAt(0) -
            startChar.charCodeAt(0), startChar.charCodeAt(0)))
}

类型化函数

function range(size:number, startAt:number = 0):ReadonlyArray<number> {
    return [...Array(size).keys()].map(i => i + startAt);
}

function characterRange(startChar:string, endChar:string):ReadonlyArray<string> {
    return String.fromCharCode(...range(endChar.charCodeAt(0) -
            startChar.charCodeAt(0), startChar.charCodeAt(0)))
}

lodash.js_.range（）函数

_.range(10);
 => [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
_.range(1, 11);
 => [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
_.range(0, 30, 5);
 => [0, 5, 10, 15, 20, 25]
_.range(0, -10, -1);
 => [0, -1, -2, -3, -4, -5, -6, -7, -8, -9]
String.fromCharCode(..._.range('A'.charCodeAt(0), 'D'.charCodeAt(0) + 1));
 => "ABCD"

没有库的旧非es6浏览器：

Array.apply(null, Array(5)).map(function (_, i) {return i;});
 => [0, 1, 2, 3, 4]

console.log（[…Array（5）.keys（）]）；

（ES6归功于尼尔斯·彼得索恩和其他评论者）

使用范围（[start，]stop[，step]）签名完成ES6实现：

function range(start, stop, step=1){
  if(!stop){stop=start;start=0;}
  return Array.from(new Array(int((stop-start)/step)), (x,i) => start+ i*step)
}

如果要自动负步进，请添加

if(stop<start)step=-Math.abs(step)

或者更简单地说：

range=(b, e, step=1)=>{
  if(!e){e=b;b=0}
  return Array.from(new Array(int((e-b)/step)), (_,i) => b<e? b+i*step : b-i*step)
}

如果你有巨大的射程，看看保罗·莫雷蒂的发电机方法

这是我用于数字范围的方法：

const rangeFrom0 = end => [...Array(end)].map((_, index) => index);

or

const rangeExcEnd = (start, step, end) => [...Array(end - start + 1)]
   .map((_, index) => index + start)
   .filter(x => x % step === start % step);

要紧密复制的类型脚本函数

/**
 * Create a generator from 0 to stop, useful for iteration. Similar to range in Python.
 * See: https://stackoverflow.com/questions/3895478/does-javascript-have-a-method-like-range-to-generate-a-range-within-the-supp
 * See: https://docs.python.org/3/library/stdtypes.html#ranges
 * @param {number | BigNumber} stop
 * @returns {Iterable<number>}
 */
export function range(stop: number | BigNumber): Iterable<number>
/**
 * Create a generator from start to stop, useful for iteration. Similar to range in Python.
 * See: https://stackoverflow.com/questions/3895478/does-javascript-have-a-method-like-range-to-generate-a-range-within-the-supp
 * See: https://docs.python.org/3/library/stdtypes.html#ranges
 * @param {number | BigNumber} start
 * @param {number | BigNumber} stop
 * @returns {Iterable<number>}
 */
export function range(
  start: number | BigNumber,
  stop: number | BigNumber,
): Iterable<number>

/**
 * Create a generator from start to stop while skipping every step, useful for iteration. Similar to range in Python.
 * See: https://stackoverflow.com/questions/3895478/does-javascript-have-a-method-like-range-to-generate-a-range-within-the-supp
 * See: https://docs.python.org/3/library/stdtypes.html#ranges
 * @param {number | BigNumber} start
 * @param {number | BigNumber} stop
 * @param {number | BigNumber} step
 * @returns {Iterable<number>}
 */
export function range(
  start: number | BigNumber,
  stop: number | BigNumber,
  step: number | BigNumber,
): Iterable<number>
export function* range(a: unknown, b?: unknown, c?: unknown): Iterable<number> {
  const getNumber = (val: unknown): number =>
    typeof val === 'number' ? val : (val as BigNumber).toNumber()
  const getStart = () => (b === undefined ? 0 : getNumber(a))
  const getStop = () => (b === undefined ? getNumber(a) : getNumber(b))
  const getStep = () => (c === undefined ? 1 : getNumber(c))

  for (let i = getStart(); i < getStop(); i += getStep()) {
    yield i
  }
}

我的实施

export function stringRange(a: string, b: string) {
    let arr = [a + ''];

    const startPrefix = a.match(/([\D])+/g);
    const endPrefix = b.match(/([\D])+/g);

    if ((startPrefix || endPrefix) && (Array.isArray(startPrefix) && startPrefix[0]) !== (Array.isArray(endPrefix) && endPrefix[0])) {
        throw new Error('Series number does not match');
    }

    const startNum = a.match(/([\d])+/g);
    const endNum = b.match(/([\d])+/g);

    if (!startNum || !endNum) {
        throw new Error('Range is not valid');
    }

    let start = parseInt(startNum[0], 10);
    let end = parseInt(endNum[0], 10);

    if (start > end) {
        throw new Error('Ending value should be lessesr that starting value');
    }

    while (start !== end) {
        start++;
        arr.push(startPrefix ? startPrefix[0] + (start + '').padStart(startNum[0].length, '0') : start + '');

    }

    return arr;
}

样本结果

// console.log(range('0', '10'));
// console.log(range('10', '10')); 
// console.log(range('10', '20'));
// console.log(range('10', '20000'));
// console.log(range('ABC10', 'ABC23'));
// console.log(range('ABC10', 'ABC2300'));
// console.log(range('ABC10', 'ABC09')); --> Failure case
// console.log(range('10', 'ABC23')); --> Failure case
// console.log(range('ABC10', '23')); --> Failure case