我从谷歌搜索开始,找到了如何在标准SQL中写INSERT如果不存在查询,其中讨论了互斥表。

我有一个包含1400万条记录的表。如果我想以相同的格式添加更多的数据,是否有一种方法可以确保我想要插入的记录不存在,而不使用一对查询(即,一个要检查的查询和一个要插入的查询是结果集为空)?

如果字段已经存在,对字段的唯一约束是否保证插入将失败?

似乎只有一个约束,当我通过PHP发出插入时,脚本就会出错。


当前回答

有几个答案,涵盖如何解决这个问题,如果你有一个唯一的索引,你可以检查与ON DUPLICATE KEY或插入忽略。但情况并非总是如此,由于UNIQUE有长度限制(1000字节),您可能无法更改它。例如,我必须在WordPress中使用元数据(wp_postmeta)。

最后我用两个问题解决了这个问题:

UPDATE wp_postmeta SET meta_value = ? WHERE meta_key = ? AND post_id = ?;
INSERT INTO wp_postmeta (post_id, meta_key, meta_value) SELECT DISTINCT ?, ?, ? FROM wp_postmeta WHERE NOT EXISTS(SELECT * FROM wp_postmeta WHERE meta_key = ? AND post_id = ?);

查询1是一个常规的UPDATE查询,当相关数据集不存在时没有任何影响。查询2是一个依赖于NOT EXISTS的INSERT,即只有当数据集不存在时才执行INSERT。

其他回答

使用INSERT IGNORE INTO表。

还有INSERT…ON DUPLICATE KEY UPDATE语法,你可以在13.2.6.2 INSERT…打开重复的键更新语句。


根据谷歌的webcache,帖子来自bogdan.org.ua:

18th October 2007 To start: as of the latest MySQL, syntax presented in the title is not possible. But there are several very easy ways to accomplish what is expected using existing functionality. There are 3 possible solutions: using INSERT IGNORE, REPLACE, or INSERT … ON DUPLICATE KEY UPDATE. Imagine we have a table: CREATE TABLE `transcripts` ( `ensembl_transcript_id` varchar(20) NOT NULL, `transcript_chrom_start` int(10) unsigned NOT NULL, `transcript_chrom_end` int(10) unsigned NOT NULL, PRIMARY KEY (`ensembl_transcript_id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; Now imagine that we have an automatic pipeline importing transcripts meta-data from Ensembl, and that due to various reasons the pipeline might be broken at any step of execution. Thus, we need to ensure two things:

反复执行的管道不会破坏我们的 >数据库

repeated executions will not die due to ‘duplicate > primary key’ errors. Method 1: using REPLACE It’s very simple: REPLACE INTO `transcripts` SET `ensembl_transcript_id` = 'ENSORGT00000000001', `transcript_chrom_start` = 12345, `transcript_chrom_end` = 12678; If the record exists, it will be overwritten; if it does not yet exist, it will be created. However, using this method isn’t efficient for our case: we do not need to overwrite existing records, it’s fine just to skip them. Method 2: using INSERT IGNORE Also very simple: INSERT IGNORE INTO `transcripts` SET `ensembl_transcript_id` = 'ENSORGT00000000001', `transcript_chrom_start` = 12345, `transcript_chrom_end` = 12678; Here, if the ‘ensembl_transcript_id’ is already present in the database, it will be silently skipped (ignored). (To be more precise, here’s a quote from MySQL reference manual: “If you use the IGNORE keyword, errors that occur while executing the INSERT statement are treated as warnings instead. For example, without IGNORE, a row that duplicates an existing UNIQUE index or PRIMARY KEY value in the table causes a duplicate-key error and the statement is aborted.”.) If the record doesn’t yet exist, it will be created. This second method has several potential weaknesses, including non-abortion of the query in case any other problem occurs (see the manual). Thus it should be used if previously tested without the IGNORE keyword. Method 3: using INSERT … ON DUPLICATE KEY UPDATE: Third option is to use INSERT … ON DUPLICATE KEY UPDATE syntax, and in the UPDATE part just do nothing do some meaningless (empty) operation, like calculating 0+0 (Geoffray suggests doing the id=id assignment for the MySQL optimization engine to ignore this operation). Advantage of this method is that it only ignores duplicate key events, and still aborts on other errors. As a final notice: this post was inspired by Xaprb. I’d also advise to consult his other post on writing flexible SQL queries.

下面是一个PHP函数,它只在表中不存在所有指定列的值时插入一行。

If one of the columns differ, the row will be added. If the table is empty, the row will be added. If a row exists where all the specified columns have the specified values, the row won't be added. function insert_unique($table, $vars) { if (count($vars)) { $table = mysql_real_escape_string($table); $vars = array_map('mysql_real_escape_string', $vars); $req = "INSERT INTO `$table` (`". join('`, `', array_keys($vars)) ."`) "; $req .= "SELECT '". join("', '", $vars) ."' FROM DUAL "; $req .= "WHERE NOT EXISTS (SELECT 1 FROM `$table` WHERE "; foreach ($vars AS $col => $val) $req .= "`$col`='$val' AND "; $req = substr($req, 0, -5) . ") LIMIT 1"; $res = mysql_query($req) OR die(); return mysql_insert_id(); } return False; }

使用示例:

<?php
  insert_unique('mytable', array(
    'mycolumn1' => 'myvalue1',
    'mycolumn2' => 'myvalue2',
    'mycolumn3' => 'myvalue3'
    )
  );
?>

在MySQL中,ON DUPLICATE KEY UPDATE或INSERT IGNORE可以是可行的解决方案。


一个基于mysql.com的ON DUPLICATE KEY UPDATE更新示例:

INSERT INTO table (a,b,c) VALUES (1,2,3)
  ON DUPLICATE KEY UPDATE c=c+1;

UPDATE table SET c=c+1 WHERE a=1;

一个基于mysql.com的INSERT IGNORE示例

INSERT [LOW_PRIORITY | DELAYED | HIGH_PRIORITY] [IGNORE]
    [INTO] tbl_name [(col_name,...)]
    {VALUES | VALUE} ({expr | DEFAULT},...),(...),...
    [ ON DUPLICATE KEY UPDATE
      col_name=expr
        [, col_name=expr] ... ]

Or:

INSERT [LOW_PRIORITY | DELAYED | HIGH_PRIORITY] [IGNORE]
    [INTO] tbl_name
    SET col_name={expr | DEFAULT}, ...
    [ ON DUPLICATE KEY UPDATE
      col_name=expr
        [, col_name=expr] ... ]

Or:

INSERT [LOW_PRIORITY | HIGH_PRIORITY] [IGNORE]
    [INTO] tbl_name [(col_name,...)]
    SELECT ...
    [ ON DUPLICATE KEY UPDATE
      col_name=expr
        [, col_name=expr] ... ]
INSERT INTO table_name (columns) VALUES (values) ON CONFLICT (id) DO NOTHING;

在没有已知主键的情况下更新或插入

如果你已经有一个唯一的或主键,其他的答案是INSERT INTO…重复密钥更新…或REPLACE INTO…应该工作正常(请注意,如果存在则将replace转换为delete,然后插入-因此不会部分更新现有值)。

但是,如果您有some_column_id和some_type的值,它们的组合已知是唯一的。如果some_value存在,则更新,如果不存在则插入。而且您希望在一个查询中完成它(以避免使用事务)。这可能是一个解决方案:

INSERT INTO my_table (id, some_column_id, some_type, some_value)
SELECT t.id, t.some_column_id, t.some_type, t.some_value
FROM (
    SELECT id, some_column_id, some_type, some_value
    FROM my_table
    WHERE some_column_id = ? AND some_type = ?
    UNION ALL
    SELECT s.id, s.some_column_id, s.some_type, s.some_value
    FROM (SELECT NULL AS id, ? AS some_column_id, ? AS some_type, ? AS some_value) AS s
) AS t
LIMIT 1
ON DUPLICATE KEY UPDATE
some_value = ?

基本上,查询是这样执行的(没有看起来那么复杂):

Select an existing row via the WHERE clause match. Union that result with a potential new row (table s), where the column values are explicitly given (s.id is NULL, so it will generate a new auto-increment identifier). If an existing row is found, then the potential new row from table s is discarded (due to LIMIT 1 on table t), and it will always trigger an ON DUPLICATE KEY which will UPDATE the some_value column. If an existing row is not found, then the potential new row is inserted (as given by table s).

注意:关系数据库中的每个表都应该至少有一个主自动递增id列。如果你没有这个,那就加进去,即使你第一眼不需要。这绝对是这个“把戏”所需要的。