约翰的答案是正确的。当我处理参数时，我还需要URLSearchParams接口:

this.props.history.push({
    pathname: '/client',
    search: "?" + new URLSearchParams({clientId: clientId}).toString()
})

你可能还需要用一个withRouter HOC来包装你的组件。export default with throuter (YourComponent);

你可以使用钩子useHistory 确保你使用的是基于函数的组件 在顶部导入这个

import {useHistory} from "react-router-dom"

在你的组件中，

const history = useHistory()
history.push({
    pathname: window.location.pathname,
    search: '?color=blue'
})

约翰的答案是正确的。当我处理参数时，我还需要URLSearchParams接口:

this.props.history.push({
    pathname: '/client',
    search: "?" + new URLSearchParams({clientId: clientId}).toString()
})

你可能还需要用一个withRouter HOC来包装你的组件。export default with throuter (YourComponent);

对于react-router v4.3

const addQuery = (key, value) => {
  let pathname = props.location.pathname;
  // returns path: '/app/books'
  let searchParams = new URLSearchParams(props.location.search);
  // returns the existing query string: '?type=fiction&author=fahid'
  searchParams.set(key, value);
  this.props.history.push({
    pathname: pathname,
    search: searchParams.toString()
  });
};

const removeQuery = (key) => {
  let pathname = props.location.pathname;
  // returns path: '/app/books'
  let searchParams = new URLSearchParams(props.location.search);
  // returns the existing query string: '?type=fiction&author=fahid'
  searchParams.delete(key);
  this.props.history.push({
    pathname: pathname,
    search: searchParams.toString()
  });
};

function SomeComponent({ location }) {
  return <div>
    <button onClick={ () => addQuery('book', 'react')}>search react books</button>
    <button onClick={ () => removeQuery('book')}>remove search</button>
  </div>;
}

要了解更多关于URLSearchParams:

var paramsString = "q=URLUtils.searchParams&topic=api";
var searchParams = new URLSearchParams(paramsString);

//Iterate the search parameters.
for (let p of searchParams) {
  console.log(p);
}

searchParams.has("topic") === true; // true
searchParams.get("topic") === "api"; // true
searchParams.getAll("topic"); // ["api"]
searchParams.get("foo") === null; // true
searchParams.append("topic", "webdev");
searchParams.toString(); // "q=URLUtils.searchParams&topic=api&topic=webdev"
searchParams.set("topic", "More webdev");
searchParams.toString(); // "q=URLUtils.searchParams&topic=More+webdev"
searchParams.delete("topic");
searchParams.toString(); // "q=URLUtils.searchParams"

我更喜欢你使用下面的ES6风格的函数:

getQueryStringParams = query => {
    return query
        ? (/^[?#]/.test(query) ? query.slice(1) : query)
            .split('&')
            .reduce((params, param) => {
                    let [key, value] = param.split('=');
                    params[key] = value ? decodeURIComponent(value.replace(/\+/g, ' ')) : '';
                    return params;
                }, {}
            )
        : {}
};

对于React Router v6+，只需使用新的useSearchParams钩子(特别是setSearchParams):

const [searchParams, setSearchParams] = useSearchParams()

setSearchParams(`?${new URLSearchParams({ paramName: 'whatever' })}`)

对于React Router v5使用useHistory:

const history = useHistory()

history.push({
    pathname: '/the-path',
    search: `?${new URLSearchParams({ paramName: 'whatever' })}`
})

URLSearchParams只是一个可选的方便助手。