PJL是对的。 我采纳了他的建议，我是这样做的:

为fragment定义的全局变量: attachingActivityLock = new Object(); private boolean syncVariable = false; 实现

@Override onAttach(Activity Activity) { super.onAttach(活动); synchronized (attachingActivityLock) { syncVariable = true; attachingActivityLock.notifyAll (); ｝ ｝

3.我在线程中包装了我的函数，在那里我需要调用getActivity()，因为如果它将在主线程上运行，我将用步骤4阻塞线程。onAttach()将永远不会被调用。

    Thread processImage = new Thread(new Runnable() {

        @Override
        public void run() {
            processImage();
        }
    });
    processImage.start();

4所示。在我的函数中，我需要调用getActivity()，我使用这个(在调用getActivity()之前)

    synchronized (attachingActivityLock) {
        while(!syncVariable){
            try {
                attachingActivityLock.wait();
            } catch (InterruptedException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
        }
    }

如果你有一些UI更新，记得在UI线程上运行它们。我需要更新ImgeView，所以我做了:

image.post(new Runnable() {

    @Override
    public void run() {
        image.setImageBitmap(imageToShow);
    }
});

请按照以下步骤操作。我想这会对你有帮助。

private boolean isVisibleToUser = false;
private boolean isExecutedOnce = false;


@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
    View root = inflater.inflate(R.layout.fragment_my, container, false);
    if (isVisibleToUser && !isExecutedOnce) {
        executeWithActivity(getActivity());
    }
    return root;
}

@Override
public void setUserVisibleHint(boolean isVisibleToUser) {
    super.setUserVisibleHint(isVisibleToUser);
    this.isVisibleToUser = isVisibleToUser;
    if (isVisibleToUser && getActivity()!=null) {
        isExecutedOnce =true;
        executeWithActivity(getActivity());
    }
}


private void executeWithActivity(Activity activity){
    //Do what you have to do when page is loaded with activity

}

PJL是对的。 我采纳了他的建议，我是这样做的:

为fragment定义的全局变量: attachingActivityLock = new Object(); private boolean syncVariable = false; 实现

@Override onAttach(Activity Activity) { super.onAttach(活动); synchronized (attachingActivityLock) { syncVariable = true; attachingActivityLock.notifyAll (); ｝ ｝

3.我在线程中包装了我的函数，在那里我需要调用getActivity()，因为如果它将在主线程上运行，我将用步骤4阻塞线程。onAttach()将永远不会被调用。

    Thread processImage = new Thread(new Runnable() {

        @Override
        public void run() {
            processImage();
        }
    });
    processImage.start();

4所示。在我的函数中，我需要调用getActivity()，我使用这个(在调用getActivity()之前)

    synchronized (attachingActivityLock) {
        while(!syncVariable){
            try {
                attachingActivityLock.wait();
            } catch (InterruptedException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
        }
    }

如果你有一些UI更新，记得在UI线程上运行它们。我需要更新ImgeView，所以我做了:

image.post(new Runnable() {

    @Override
    public void run() {
        image.setImageBitmap(imageToShow);
    }
});

那些仍然有问题的onAttach(活动活动)，它只是改变了上下文-

    @Override
public void onAttach(Context context) {
    super.onAttach(context);
    this.context = context;
}

在大多数情况下，保存上下文对您来说就足够了——例如，如果您想执行getResources()，您可以直接从上下文执行。如果你仍然需要将上下文放入你的活动中，那么就这样做吧

 @Override
public void onAttach(Context context) {
    super.onAttach(context);
    mActivity a; //Your activity class - will probably be a global var.
    if (context instanceof mActivity){
        a=(mActivity) context;
    }
}

由user1868713建议。

The other answers that suggest keeping a reference to the activity in onAttach are just suggesting a bandaid to the real problem. When getActivity returns null it means that the Fragment is not attached to the Activity. Most commonly this happens when the Activity has gone away due to rotation or the Activity being finished but the Fragment still has some kind of callback listener registered preventing it from being garbage collected. When the listener gets called if you need to do something with the Activity but the Activity is gone there isn't much you can do. In your code you should just check getActivity() != null and if it's not there then don't do anything. If you keep a reference to the Activity that is gone you are preventing the Activity from being garbage collected. Any UI things you might try to do won't be seen by the user. I can imagine some situations where in the callback listener you want to have a Context for something non-UI related, in those cases it probably makes more sense to get the Application context. Note that the only reason that the onAttach trick isn't a big memory leak is because normally after the callback listener executes it won't be needed anymore and can be garbage collected along with the Fragment, all its View's and the Activity context. If you setRetainInstance(true) there is a bigger chance of a memory leak because the Activity field will also be retained but after rotation that could be the previous Activity not the current one.

我正在使用OkHttp，我刚刚遇到了这个问题。

@thucnguyen的第一部分是正确的。

这发生在您在另一个线程中调用getActivity()时，该线程在片段被删除后结束。典型的情况是在HTTP请求完成时调用getActivity()(例如Toast)(例如onResponse)。

一些HTTP调用甚至在活动关闭后仍在执行(因为完成HTTP请求可能需要一段时间)。然后，我通过HttpCallback试图更新一些片段字段，并在尝试getActivity()时得到一个空异常。

http.newCall(request).enqueue(new Callback(...
  onResponse(Call call, Response response) {
    ...
    getActivity().runOnUiThread(...) // <-- getActivity() was null when it had been destroyed already

IMO的解决方案是防止当片段不再活跃时发生回调(不仅仅是Okhttp)。

解决办法:预防。

如果你看一下片段的生命周期(更多信息在这里)，你会注意到有onAttach(Context Context)和onDetach()方法。它们分别在Fragment属于一个活动之后和停止之前被调用。

这意味着我们可以通过在onDetach方法中控制它来防止回调的发生。

@Override
public void onAttach(Context context) {
    super.onAttach(context);

    // Initialize HTTP we're going to use later.
    http = new OkHttpClient.Builder().build();
}

@Override
public void onDetach() {
    super.onDetach();

    // We don't want to receive any more information about the current HTTP calls after this point.
    // With Okhttp we can simply cancel the on-going ones (credits to https://github.com/square/okhttp/issues/2205#issuecomment-169363942).
    for (Call call : http.dispatcher().queuedCalls()) {
        call.cancel();
    }
    for (Call call : http.dispatcher().runningCalls()) {
        call.cancel();
    }
}