我想在不退出的情况下捕获和记录异常,例如,
try:
do_stuff()
except Exception as err:
print(Exception, err)
# I want to print the entire traceback here,
# not just the exception name and details
我想打印与抛出异常时打印的完全相同的输出,而不使用try/,只是拦截异常,并且我不希望它退出程序。
我想在不退出的情况下捕获和记录异常,例如,
try:
do_stuff()
except Exception as err:
print(Exception, err)
# I want to print the entire traceback here,
# not just the exception name and details
我想打印与抛出异常时打印的完全相同的输出,而不使用try/,只是拦截异常,并且我不希望它退出程序。
当前回答
您需要traceback模块。它将允许您像Python通常那样打印堆栈转储。特别是,print_last函数将打印最后一个异常和堆栈跟踪。
其他回答
这是我把错误写在日志文件和控制台的解决方案:
import logging, sys
import traceback
logging.basicConfig(filename='error.log', level=logging.DEBUG)
def handle_exception(exc_type, exc_value, exc_traceback):
if issubclass(exc_type, KeyboardInterrupt):
sys.__excepthook__(exc_type, exc_value, exc_traceback)
return
exc_info=(exc_type, exc_value, exc_traceback)
logging.critical("\nDate:" + str(datetime.datetime.now()), exc_info=(exc_type, exc_value, exc_traceback))
print("An error occured, check error.log to see the error details")
traceback.print_exception(*exc_info)
sys.excepthook = handle_exception
在python3(适用于3.9)中,我们可以定义一个函数,并可以在任何需要打印详细信息的地方使用它。
import traceback
def get_traceback(e):
lines = traceback.format_exception(type(e), e, e.__traceback__)
return ''.join(lines)
try:
1/0
except Exception as e:
print('------Start--------')
print(get_traceback(e))
print('------End--------')
try:
spam(1,2)
except Exception as e:
print('------Start--------')
print(get_traceback(e))
print('------End--------')
输出如下所示:
bash-3.2$ python3 /Users/soumyabratakole/PycharmProjects/pythonProject/main.py
------Start--------
Traceback (most recent call last):
File "/Users/soumyabratakole/PycharmProjects/pythonProject/main.py", line 26, in <module>
1/0
ZeroDivisionError: division by zero
------End--------
------Start--------
Traceback (most recent call last):
File "/Users/soumyabratakole/PycharmProjects/pythonProject/main.py", line 33, in <module>
spam(1,2)
NameError: name 'spam' is not defined
------End--------
Python 3解决方案
stacktrace_helper.py:
from linecache import getline
import sys
import traceback
def get_stack_trace():
exc_type, exc_value, exc_tb = sys.exc_info()
trace = traceback.format_stack()
trace = list(filter(lambda x: ("\\lib\\" not in x and "/lib/" not in x and "stacktrace_helper.py" not in x), trace))
ex_type = exc_type.__name__
ex_line = exc_tb.tb_lineno
ex_file = exc_tb.tb_frame.f_code.co_filename
ex_message = str(exc_value)
line_code = ""
try:
line_code = getline(ex_file, ex_line).strip()
except:
pass
trace.insert(
0, f'File "{ex_file}", line {ex_line}, line_code: {line_code} , ex: {ex_type} {ex_message}',
)
return trace
def get_stack_trace_str(msg: str = ""):
trace = list(get_stack_trace())
trace_str = "\n".join(list(map(str, trace)))
trace_str = msg + "\n" + trace_str
return trace_str
import io
import traceback
try:
call_code_that_fails()
except:
errors = io.StringIO()
traceback.print_exc(file=errors) # Instead of printing directly to stdout, the result can be further processed
contents = str(errors.getvalue())
print(contents)
errors.close()
如果你已经有了一个Error对象,并且你想打印整个东西,你需要做这个有点尴尬的调用:
import traceback
traceback.print_exception(type(err), err, err.__traceback__)
没错,print_exception接受三个位置参数:异常的类型、实际的异常对象和异常自身的内部回溯属性。
在python 3.5或更高版本中,类型(err)是可选的…但它是一个位置参数,所以你仍然需要显式地在它的位置传递None。
traceback.print_exception(None, err, err.__traceback__)
我不知道为什么所有这些不只是traceback.print_exception(err)。为什么你会想打印出一个错误,以及一个回溯,而不是属于该错误的,这超出了我的理解。