如何在JavaScript中创建GUID(全球独特识别器)?GUID/UUID应该至少有32个字符,并且应该保持在ASCII范围内,以避免在通过它们时遇到麻烦。
我不确定在所有浏览器上有哪些习惯,如何“随机”和种植内置的随机号码发电机等。
如何在JavaScript中创建GUID(全球独特识别器)?GUID/UUID应该至少有32个字符,并且应该保持在ASCII范围内,以避免在通过它们时遇到麻烦。
我不确定在所有浏览器上有哪些习惯,如何“随机”和种植内置的随机号码发电机等。
当前回答
这里是一个方法,使用真实的随机通过 random.org 生成 RFC4122 如果错误,它会回到浏览器的内置加密图书馆,这应该几乎是相同的好。
async function UUID() {
//get 31 random hex characters
return (await (async () => {
let output;
try {
//try from random.org
output = (await (
await fetch('https://www.random.org/integers/?num=31&min=0&max=15&col=31&base=16&format=plain&rnd=new')
).text())
//get rid of whitespace
.replace(/[^0-9a-fA-F]+/g, '')
;
if (output.length != 31)
throw '';
}
catch {
output = '';
try {
//failing that, try getting 16 8-bit digits from crypto
for (let num of crypto.getRandomValues(new Uint8Array(16)))
//interpret as 32 4-bit hex numbers
output += (num >> 4).toString(16) + (num & 15).toString(16);
//we only want 31
output = output.substr(1);
}
catch {
//failing THAT, use Math.random
while (output.length < 31)
output += (0 | Math.random() * 16).toString(16);
}
}
return output;
})())
//split into appropriate sections, and set the 15th character to 4
.replace(/^(.{8})(.{4})(.{3})(.{4})/, '$1-$2-4$3-$4-')
//force character 20 to the correct range
.replace(/(?<=-)[^89abAB](?=[^-]+-[^-]+$)/, (num) => (
(parseInt(num, 16) % 4 + 8).toString(16)
))
;
}
此分類上一篇
其他回答
一个简单的解决方案来创建一个独特的识别是使用一个时间标记,并添加一个随机号码。
下面的功能将产生类型的随机序列: uuid-14d93eb1b9b4533e6. 不需要产生32个字符的随机序列. 在这种情况下,16个字符的随机序列不足以提供JavaScript中的独特 UUID。
var createUUID = function() {
return "uuid-" + ((new Date).getTime().toString(16) + Math.floor(1E7*Math.random()).toString(16));
}
我想了解布罗法的答案,所以我扩展了它并添加了评论:
var uuid = function () {
return 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(
/[xy]/g,
function (match) {
/*
* Create a random nibble. The two clever bits of this code:
*
* - Bitwise operations will truncate floating point numbers
* - For a bitwise OR of any x, x | 0 = x
*
* So:
*
* Math.random * 16
*
* creates a random floating point number
* between 0 (inclusive) and 16 (exclusive) and
*
* | 0
*
* truncates the floating point number into an integer.
*/
var randomNibble = Math.random() * 16 | 0;
/*
* Resolves the variant field. If the variant field (delineated
* as y in the initial string) is matched, the nibble must
* match the mask (where x is a do-not-care bit):
*
* 10xx
*
* This is achieved by performing the following operations in
* sequence (where x is an intermediate result):
*
* - x & 0x3, which is equivalent to x % 3
* - x | 0x8, which is equivalent to x + 8
*
* This results in a nibble between 8 inclusive and 11 exclusive,
* (or 1000 and 1011 in binary), all of which satisfy the variant
* field mask above.
*/
var nibble = (match == 'y') ?
(randomNibble & 0x3 | 0x8) :
randomNibble;
/*
* Ensure the nibble integer is encoded as base 16 (hexadecimal).
*/
return nibble.toString(16);
}
);
};
根據 RFC 4122 的 UUID (Universally Unique IDentifier),也被稱為 GUID (Globally Unique IDentifier),是為提供某些獨特性保證而設計的識別。
虽然可以在JavaScript代码的几个行中实施符合RFC的UUID(例如,请参见 @broofa的答案,下面),但有几个常见的漏洞:
无效 ID 格式(UUID 必须是“xxxxxx-xxxx-Mxxx-Nxxx-xxxxxxxxxxxx”的格式,其中 x 是 [0-9, a-f] M 是 [1-5] 的格式,而 N 是 [8, 9, a 或 b] 使用低质量的随机性来源(如 Math.random)
因此,开发人员为生产环境编写代码被鼓励使用严格,良好的实施,如新模块。
// RFC 4122
//
// A UUID is 128 bits long
//
// String representation is five fields of 4, 2, 2, 2, and 6 bytes.
// Fields represented as lowercase, zero-filled, hexadecimal strings, and
// are separated by dash characters
//
// A version 4 UUID is generated by setting all but six bits to randomly
// chosen values
var uuid = [
Math.random().toString(16).slice(2, 10),
Math.random().toString(16).slice(2, 6),
// Set the four most significant bits (bits 12 through 15) of the
// time_hi_and_version field to the 4-bit version number from Section
// 4.1.3
(Math.random() * .0625 /* 0x.1 */ + .25 /* 0x.4 */).toString(16).slice(2, 6),
// Set the two most significant bits (bits 6 and 7) of the
// clock_seq_hi_and_reserved to zero and one, respectively
(Math.random() * .25 /* 0x.4 */ + .5 /* 0x.8 */).toString(16).slice(2, 6),
Math.random().toString(16).slice(2, 14)].join('-');
var uuid = function() {
var buf = new Uint32Array(4);
window.crypto.getRandomValues(buf);
var idx = -1;
return 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(/[xy]/g, function(c) {
idx++;
var r = (buf[idx>>3] >> ((idx%8)*4))&15;
var v = c == 'x' ? r : (r&0x3|0x8);
return v.toString(16);
});
};
这个版本是基于Briguy37的答案和一些Bitwise运营商从泡沫中提取Nibble大小的窗户。
它应该遵守RFC类型4(随机)方案,因为我上次遇到麻烦与Java的UUID不符合的UUID。