我为此做了一个包裹。与这里的大多数其他答案不同，它不会接受未经处理的拒绝。

npm install p-state

import timers from 'timers/promises';
import {promiseStateSync} from 'p-state';

const timeoutPromise = timers.setTimeout(100);

console.log(promiseStateSync(timeoutPromise));
//=> 'pending'

await timeoutPromise;

console.log(promiseStateSync(timeoutPromise));
//=> 'fulfilled'

你可以在Promise.prototype中添加一个方法。它是这样的:

编辑:第一个解决方案不能正常工作，就像这里的大多数答案一样。它返回“pending”直到异步函数“。然后”被调用，这不是立即发生的。(使用Promise.race的解决方案也是如此)。我的第二个解决方案解决了这个问题。

if (window.Promise) {
    Promise.prototype.getState = function () {
        if (!this.state) {
            this.state = "pending";
            var that = this;
            this.then(
                function (v) {
                    that.state = "resolved";
                    return v;
                },
                function (e) {
                    that.state = "rejected";
                    return e;
                });
        }
        return this.state;
    };
}

你可以在任何承诺上使用它。为例:

myPromise = new Promise(myFunction);
console.log(myPromise.getState()); // pending|resolved|rejected

第二个(也是正确的)解决方案:

if (window.Promise) {
    Promise.stateable = function (func) {
        var state = "pending";
        var pending = true;
        var newPromise = new Promise(wrapper);
        newPromise.state = state;
        return newPromise;
        function wrapper(resolve, reject) {
            func(res, rej);
            function res(e) {
                resolve(e);
                if (pending) {
                    if (newPromise)
                        newPromise.state = "resolved";
                    else
                        state = "resolved";
                    pending = false;
                }
            }
            function rej(e) {
                reject(e);
                if (pending) {
                    if (newPromise)
                        newPromise.state = "rejected";
                    else
                        state = "rejected";
                    pending = false;
                }
            }
        }
    };
}

并使用它:

注意:在这个解决方案中，您不必使用“new”操作符。

myPromise = Promise.stateable(myFunction);
console.log(myPromise.state); // pending|resolved|rejected

Promise-status-async可以做到。它是异步的，但它不使用然后等待承诺被解决。

const {promiseStatus} = require('promise-status-async');
// ...
if (await promiseStatus(promise) === 'pending') {
    const idle = new Promise(function(resolve) {
        // can do some IDLE job meanwhile
    });
    return idle;
}

我发现这个解决方案很简单，并且允许我继续使用本机承诺，但添加了有用的同步检查。我也不需要动用整个承诺库。

注意:只有在当前执行线程中出现某种中断，允许promise在检查同步结构之前执行时，这才有效。这使得它比我最初想象的用处更有限——尽管对我的用例仍然有用(感谢Benjamin Gruenbaum指出这一点)。

/**
 * This function allow you to modify a JS Promise by adding some status properties.
 * Based on: http://stackoverflow.com/questions/21485545/is-there-a-way-to-tell-if-an-es6-promise-is-fulfilled-rejected-resolved
 * But modified according to the specs of promises : https://promisesaplus.com/
 */
function MakeQuerablePromise(promise) {
    // Don't modify any promise that has been already modified.
    if (promise.isFulfilled) return promise;

    // Set initial state
    var isPending = true;
    var isRejected = false;
    var isFulfilled = false;

    // Observe the promise, saving the fulfillment in a closure scope.
    var result = promise.then(
        function(v) {
            isFulfilled = true;
            isPending = false;
            return v; 
        }, 
        function(e) {
            isRejected = true;
            isPending = false;
            throw e; 
        }
    );

    result.isFulfilled = function() { return isFulfilled; };
    result.isPending = function() { return isPending; };
    result.isRejected = function() { return isRejected; };
    return result;
}

wrappedPromise = MakeQueryablePromise(Promise.resolve(3)); 
setTimeout(function() {console.log(wrappedPromise.isFulfilled())}, 1);

来自https://ourcodeworld.com/articles/read/317/how-to-check-if-a-javascript-promise-has-been-fulfilled-rejected-or-resolved，他们的答案是:是否有一种方法来判断一个ES6承诺是否被履行/拒绝/解决?

我写了一个小的npm包promise-value，它提供了一个带有解析标志的promise包装器:

https://www.npmjs.com/package/promise-value

它还提供了对承诺值(或错误)的同步访问。这不会改变Promise对象本身，而是遵循wrap而不是extend模式。

This is older question but I was trying to do something similar. I need to keep n workers going. They are structured in a promise. I need to scan and see if they are resolved, rejected or still pending. If resolved, I need the value, if rejected do something to correct the issue or pending. If resolved or rejected I need to start another task to keep n going. I can't figure a way to do it with Promise.all or Promise.race as I keep working promises in an array and can find no way to delete them. So I create a worker that does the trick

我需要一个承诺生成器函数，返回一个承诺，根据需要解决或拒绝。它由一个函数调用，该函数设置框架以了解承诺在做什么。

在下面的代码中，生成器只是返回一个基于setTimeout的承诺。

在这里

//argObj should be of form
// {succeed: <true or false, nTimer: <desired time out>}
function promiseGenerator(argsObj) {
  let succeed = argsObj.succeed;          
  let nTimer = argsObj.nTimer;
  return new Promise((resolve, reject) => {
    setTimeout(() => {
      if (succeed) {
        resolve('ok');
      }
      else {
        reject(`fail`);
      }
    }, nTimer);
  })

}

function doWork(generatorargs) {
  let sp = { state: `pending`, value: ``, promise: "" };
  let p1 = promiseGenerator(generatorargs)
    .then((value) => {
      sp.state = "resolved";
      sp.value = value;
    })
    .catch((err) => {
      sp.state = "rejected";
      sp.value = err;
    })
  sp.promise = p1;
  return sp;
}

doWork返回一个包含promise及其状态和返回值的对象。

下面的代码运行一个循环，测试状态并创建新的工作线程以保持在3个正在运行的工作线程。

let promiseArray = [];

promiseArray.push(doWork({ succeed: true, nTimer: 1000 }));
promiseArray.push(doWork({ succeed: true, nTimer: 500 }));
promiseArray.push(doWork({ succeed: false, nTimer: 3000 }));

function loopTimerPromise(delay) {
  return new Promise((resolve, reject) => {
    setTimeout(() => {
      resolve('ok');
    }, delay)
  })
}

async function looper() {
  let nPromises = 3;      //just for breaking loop
  let nloop = 0;          //just for breaking loop
  let i;
  //let continueLoop = true;
  while (true) {
    await loopTimerPromise(900);  //execute loop every 900ms
    nloop++;
    //console.log(`promiseArray.length = ${promiseArray.length}`);
    for (i = promiseArray.length; i--; i > -1) {
      console.log(`index ${i} state: ${promiseArray[i].state}`);
      switch (promiseArray[i].state) {
        case "pending":
          break;
        case "resolved":
          nPromises++;
          promiseArray.splice(i, 1);
          promiseArray.push(doWork({ succeed: true, nTimer: 1000 }));
          break;
        case "rejected":
          //take recovery action
          nPromises++;
          promiseArray.splice(i, 1);
          promiseArray.push(doWork({ succeed: false, nTimer: 500 }));
          break;
        default:
          console.log(`error bad state in i=${i} state:${promiseArray[i].state} `)
          break;
      }
    }
    console.log(``);
    if (nloop > 10 || nPromises > 10) {
      //should do a Promise.all on remaining promises to clean them up but not for test
      break;
    }
  }
}

looper();

在node.js中测试

顺便说一句，不是在这个问题上，而是在其他类似的问题上，我讨厌有人说“你不明白”或“事情不是这样的”，我通常认为提问者知道他们想要什么。建议一个更好的方法是很好的。耐心地解释承诺如何起作用也会很好。