我在玩苹果的新Swift编程语言，遇到了一些问题…
目前我试图读取一个plist文件，在Objective-C中，我会做以下工作来获取内容作为NSDictionary:
NSString *filePath = [[NSBundle mainBundle] pathForResource:@"Config" ofType:@"plist"];
NSDictionary *dict = [[NSDictionary alloc] initWithContentsOfFile:filePath];
我如何得到一个plist作为一个字典在Swift?
我假设我可以得到路径到plist:
let path = NSBundle.mainBundle().pathForResource("Config", ofType: "plist")
当这工作(如果它是正确的?):我如何获得内容作为一个字典?
还有一个更普遍的问题:
是否可以使用默认的NS*类?我想是的……还是我遗漏了什么?据我所知，默认框架NS*类仍然有效，可以使用吗?
当前回答
在我的情况下，我创建了一个NSDictionary称为appSettings并添加所有需要的键。对于这种情况，解决方案是:
if let dict = NSBundle.mainBundle().objectForInfoDictionaryKey("appSettings") {
if let configAppToken = dict["myKeyInsideAppSettings"] as? String {
}
}
其他回答
能在一行内完成吗
var dict = NSDictionary(contentsOfFile: NSBundle.mainBundle().pathForResource("Config", ofType: "plist"))
以下是我找到的解决方案:
let levelBlocks = NSDictionary(contentsOfFile: NSBundle.mainBundle().pathForResource("LevelBlocks", ofType: "plist"))
let test: AnyObject = levelBlocks.objectForKey("Level1")
println(test) // Prints the value of test
我将测试类型设置为AnyObject，以关闭关于可能发生的意外推断的警告。
而且，它必须在类方法中完成。
访问并保存已知类型的特定值:
let value = levelBlocks.objectForKey("Level1").objectForKey("amount") as Int
println(toString(value)) // Converts value to String and prints it
Swift 4.0 iOS 11.2.6列表解析和代码解析它，基于https://stackoverflow.com/users/3647770/ashok-r上面的答案。
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<array>
<dict>
<key>identity</key>
<string>blah-1</string>
<key>major</key>
<string>1</string>
<key>minor</key>
<string>1</string>
<key>uuid</key>
<string>f45321</string>
<key>web</key>
<string>http://web</string>
</dict>
<dict>
<key>identity</key>
<string></string>
<key>major</key>
<string></string>
<key>minor</key>
<string></string>
<key>uuid</key>
<string></string>
<key>web</key>
<string></string>
</dict>
</array>
</plist>
do {
let plistXML = try Data(contentsOf: url)
var plistData: [[String: AnyObject]] = [[:]]
var propertyListFormat = PropertyListSerialization.PropertyListFormat.xml
do {
plistData = try PropertyListSerialization.propertyList(from: plistXML, options: .mutableContainersAndLeaves, format: &propertyListFormat) as! [[String:AnyObject]]
} catch {
print("Error reading plist: \(error), format: \(propertyListFormat)")
}
} catch {
print("error no upload")
}
如果我想将.plist转换为Swift字典，这是我所做的:
if let path = NSBundle.mainBundle().pathForResource("Config", ofType: "plist") {
if let dict = NSDictionary(contentsOfFile: path) as? Dictionary<String, AnyObject> {
// use swift dictionary as normal
}
}
为Swift 2.0编辑:
if let path = NSBundle.mainBundle().pathForResource("Config", ofType: "plist"), dict = NSDictionary(contentsOfFile: path) as? [String: AnyObject] {
// use swift dictionary as normal
}
为Swift 3.0编辑:
if let path = Bundle.main.path(forResource: "Config", ofType: "plist"), let dict = NSDictionary(contentsOfFile: path) as? [String: AnyObject] {
// use swift dictionary as normal
}
下面是一个基于@connor的回答的简短版本
guard let path = Bundle.main.path(forResource: "GoogleService-Info", ofType: "plist"),
let myDict = NSDictionary(contentsOfFile: path) else {
return nil
}
let value = dict.value(forKey: "CLIENT_ID") as! String?
