下面的代码来自jQuery UI自动完成:

var projects = [
    {
        value: "jquery",
        label: "jQuery",
        desc: "the write less, do more, JavaScript library",
        icon: "jquery_32x32.png"
    },
    {
        value: "jquery-ui",
        label: "jQuery UI",
        desc: "the official user interface library for jQuery",
        icon: "jqueryui_32x32.png"
    },
    {
        value: "sizzlejs",
        label: "Sizzle JS",
        desc: "a pure-JavaScript CSS selector engine",
        icon: "sizzlejs_32x32.png"
    }
];

例如,我想更改jquery-ui的desc值。我该怎么做呢?

此外,是否有更快的方法来获取数据?我的意思是给对象一个名字来获取它的数据,就像数组中的对象一样?比如jquery-ui。jquery-ui。desc = ....


当前回答

upsert(array, item) { 
        const i = array.findIndex(_item => _item.id === item.id);
        if (i > -1) {
            let result = array.filter(obj => obj.id !== item.id);
            return [...result, item]
        }
        else {
            return [...array, item]
        };
    }

其他回答

首先查找索引:

function getIndex(array, key, value) {
        var found = false;
        var i = 0;
        while (i<array.length && !found) {
          if (array[i][key]==value) {
            found = true;
            return i;
          }
          i++;
        }
      }

然后:

console.log(getIndex($scope.rides, "_id", id));

然后对这个索引做你想做的事情,比如:

美元(returnedindex)范围。someKey = "someValue";

注意:请不要使用for,因为for将检查所有的数组文档,使用while带有一个停止器,因此一旦找到它就会停止,从而更快地编写代码。

您需要知道要更改的对象的索引。这很简单

projects[1].desc= "new string";

使用map是最好的解决方案,不需要使用额外的库。(使用ES6)

const state = [
{
    userId: 1,
    id: 100,
    title: "delectus aut autem",
    completed: false
},
{
    userId: 1,
    id: 101,
    title: "quis ut nam facilis et officia qui",
    completed: false
},
{
    userId: 1,
    id: 102,
    title: "fugiat veniam minus",
    completed: false
},
{
    userId: 1,
    id: 103,
    title: "et porro tempora",
    completed: true
}]

const newState = state.map(obj =>
    obj.id === "101" ? { ...obj, completed: true } : obj
);

我们可以这样改变

const oldArray = [{username: gopal, age: 20}, {username: gopi, age: 21}]
const obj = {username: gopal, age: 25}
const result = oldArray.map(d => d.username === 'gopi' ? d.age = obj.age : d)

这很简单

使用findIndex方法查找对象的索引。 将索引存储在变量中。 做一个简单的更新,像这样:

//Initailize array of objects. let myArray = [ {id: 0, name: "Jhon"}, {id: 1, name: "Sara"}, {id: 2, name: "Domnic"}, {id: 3, name: "Bravo"} ], //Find index of specific object using findIndex method. objIndex = myArray.findIndex((obj => obj.id == 1)); //Log object to Console. console.log("Before update: ", myArray[objIndex]) //Update object's name property. myArray[objIndex].name = "Laila" //Log object to console again. console.log("After update: ", myArray[objIndex])