已经有很多好的答案，但添加这个特定的基于@HandyGold75的答案，我希望它在特定的上下文中是callabe，有一个初始的msg，加上在结束时的几秒钟的时间反馈。

from time import sleep, time


class ProgressBar:
    def __init__(self, total: float, width: int = 50, msg: str = ""):
    self.total = total
    self.width = width
    self.start: float = time()
    if msg:
        print(f"{msg}")

    def progress(self, progress: float):
        percent = self.width * ((progress) / self.total)
        bar = chr(9608) * int(percent) + "-" * (self.width - int(percent))
        print(
            f"\r|{bar}| {(100/self.width)*percent:.2f}% "
            f"[{progress} of {self.total}]",
            end="\r",
        )

    def __enter__(self):
        return self.progress

    def __exit__(self, type, value, traceback):
        end: float = time()
        print(f"\nFinished after {end - self.start: .3f} seconds.")


# USAGE
total_loops = 150
with ProgressBar(total=total_loops) as progress:
    for i in range(total_loops):
        sleep(0.01)  # Do something usefull here
        progress(i + 1)

这个进度条显示了每完成2%的点和每完成10%的数字。

import sys

def ProgressBar (num, total, nextPercent, nextPoint):
    num = float (num)
    total = float (total) - 1
    if not nextPoint:
        nextPoint = 0.0
    if not nextPercent:
        nextPoint += 2.0
        sys.stdout.write ("[0%")
        nextPercent = 10
    elif num == total:
        sys.stdout.write ("100%]\n")
        nextPercent += 10
    elif not nextPoint:
        nextPoint = 0.0
    elif num / total * 100 >= nextPercent:
        sys.stdout.write (str(int (nextPercent)) + "%")
        nextPercent += 10
    elif num / total * 100 >= nextPoint:
        sys.stdout.write (":")
        nextPoint += 2
    return (nextPercent, nextPoint)

nextPercent, nextPoint = 0, 0
total = 1000

for num in range (total):
    nextPercent, nextPoint = ProgressBar (num, total, nextPercent, nextPoint)

结果:

>>> 
[0%::::10%:::::20%:::::30%:::::40%:::::50%:::::60%:::::70%:::::80%:::::90%:::::100%]
>>> 

使用tqdm (conda install tqdm或pip install tqdm)，你可以在一秒钟内为你的循环添加一个进度计:

from time import sleep
from tqdm import tqdm
for i in tqdm(range(10)):
    sleep(3)

 60%|██████    | 6/10 [00:18<00:12,  0.33 it/s]

此外，还有一个笔记本版本:

from tqdm.notebook import tqdm
for i in tqdm(range(100)):
    sleep(3)

您可以使用tqdm。Auto代替tqdm。笔记本电脑工作在两个终端和笔记本电脑。

tqdm。Contrib包含一些辅助函数，用于执行枚举、映射和压缩等操作。在tqdm.contrib.concurrent中有并发映射。

你甚至可以使用tqdm.contrib.telegram或tqdm.contrib.discord从jupyter笔记本断开连接后将进度发送到你的手机。

下面的代码是一个相当通用的解决方案，也有一个时间消耗和剩余时间估计。你可以使用任何可迭代对象。进度条的大小固定为25个字符，但可以使用完整、半块和四分之一块字符以1%的速度显示更新。输出如下所示:

 18% |████▌                    | \ [0:00:01, 0:00:06]

代码示例:

import sys, time
from numpy import linspace

def ProgressBar(iterObj):
  def SecToStr(sec):
    m, s = divmod(sec, 60)
    h, m = divmod(m, 60)
    return u'%d:%02d:%02d'%(h, m, s)
  L = len(iterObj)
  steps = {int(x):y for x,y in zip(linspace(0, L, min(100,L), endpoint=False),
                                   linspace(0, 100, min(100,L), endpoint=False))}
  qSteps = ['', u'\u258E', u'\u258C', u'\u258A'] # quarter and half block chars
  startT = time.time()
  timeStr = '   [0:00:00, -:--:--]'
  activity = [' -',' \\',' |',' /']
  for nn,item in enumerate(iterObj):
    if nn in steps:
      done = u'\u2588'*int(steps[nn]/4.0)+qSteps[int(steps[nn]%4)]
      todo = ' '*(25-len(done))
      barStr = u'%4d%% |%s%s|'%(steps[nn], done, todo)
    if nn>0:
      endT = time.time()
      timeStr = ' [%s, %s]'%(SecToStr(endT-startT),
                             SecToStr((endT-startT)*(L/float(nn)-1)))
    sys.stdout.write('\r'+barStr+activity[nn%4]+timeStr); sys.stdout.flush()
    yield item
  barStr = u'%4d%% |%s|'%(100, u'\u2588'*25)
  timeStr = '   [%s, 0:00:00]\n'%(SecToStr(time.time()-startT))
  sys.stdout.write('\r'+barStr+timeStr); sys.stdout.flush()

# Example
s = ''
for c in ProgressBar(list('Disassemble and reassemble this string')):
  time.sleep(0.2)
  s += c
print(s)

欢迎提出改进建议或其他意见。干杯!

我喜欢加布里埃尔的答案，但我改变了它的灵活性。您可以将bar-length发送到函数，并获得您想要的任何长度的进度条。进度条的长度不能为零或负。同样，你也可以像Gabriel answer一样使用这个函数(请看例子#2)。

import sys
import time

def ProgressBar(Total, Progress, BarLength=20, ProgressIcon="#", BarIcon="-"):
    try:
        # You can't have a progress bar with zero or negative length.
        if BarLength <1:
            BarLength = 20
        # Use status variable for going to the next line after progress completion.
        Status = ""
        # Calcuting progress between 0 and 1 for percentage.
        Progress = float(Progress) / float(Total)
        # Doing this conditions at final progressing.
        if Progress >= 1.:
            Progress = 1
            Status = "\r\n"    # Going to the next line
        # Calculating how many places should be filled
        Block = int(round(BarLength * Progress))
        # Show this
        Bar = "[{}] {:.0f}% {}".format(ProgressIcon * Block + BarIcon * (BarLength - Block), round(Progress * 100, 0), Status)
        return Bar
    except:
        return "ERROR"

def ShowBar(Bar):
    sys.stdout.write(Bar)
    sys.stdout.flush()

if __name__ == '__main__':
    print("This is a simple progress bar.\n")

    # Example #1:
    print('Example #1')
    Runs = 10
    for i in range(Runs + 1):
        progressBar = "\rProgress: " + ProgressBar(10, i, Runs)
        ShowBar(progressBar)
        time.sleep(1)

    # Example #2:
    print('\nExample #2')
    Runs = 10
    for i in range(Runs + 1):
        progressBar = "\rProgress: " + ProgressBar(10, i, 20, '|', '.')
        ShowBar(progressBar)
        time.sleep(1)

    print('\nDone.')

# Example #2:
Runs = 10
for i in range(Runs + 1):
    ProgressBar(10, i)
    time.sleep(1)

结果:

这是一个简单的进度条。 示例# 1 进度:[###-------]30% 例# 2 进步 : [||||||||||||........) 60% 完成了。

它在我的程序中工作得很好。此外，我们需要添加一个计数器来指示循环时间。这个计数器作为方法update的参数。 例如:读取测试文件的所有行，并对它们进行处理。假设函数dosth()与变量i无关。

lines = open(sys.argv[1]).readlines()
i = 0
widgets=[Percentage(), Bar()]
pbar = ProgressBar(widgets=widgets,maxval=len(lines)).start()
pbar.start()
for line in lines:<pre>
    dosth();
    i += 1
    pbar.update(i)</pre>
pbar.finish()

变量i通过方法update控制pbar的状态