下面是一种技术，用于重新创建查询字符串中使用的本地表。这样做可以消除所有解析问题。

字符串可以用任何语言构建。在本例中，我使用SQL，因为这是我试图解决的原始问题。我需要一种干净的方法来在一个字符串中传递表数据，以便稍后执行。

使用用户定义的类型是可选的。创建类型只创建一次，并且可以提前完成。否则，只需在字符串中的声明中添加一个完整的表类型。

通用模式易于扩展，可用于传递更复杂的表。

-- Create a user defined type for the list.
CREATE TYPE [dbo].[StringList] AS TABLE(
    [StringValue] [nvarchar](max) NOT NULL
)

-- Create a sample list using the list table type.
DECLARE @list [dbo].[StringList]; 
INSERT INTO @list VALUES ('one'), ('two'), ('three'), ('four')

-- Build a string in which we recreate the list so we can pass it to exec
-- This can be done in any language since we're just building a string.
DECLARE @str nvarchar(max);
SET @str = 'DECLARE @list [dbo].[StringList]; INSERT INTO @list VALUES '

-- Add all the values we want to the string. This would be a loop in C++.
SELECT @str = @str + '(''' + StringValue + '''),' FROM @list

-- Remove the trailing comma so the query is valid sql.
SET @str = substring(@str, 1, len(@str)-1)

-- Add a select to test the string.
SET @str = @str + '; SELECT * FROM @list;'

-- Execute the string and see we've pass the table correctly.
EXEC(@str)

如果你有SQL Server 2008或更高版本，我会使用表值参数。

如果你不幸被困在SQL Server 2005上，你可以添加这样一个CLR函数，

[SqlFunction(
    DataAccessKind.None,
    IsDeterministic = true,
    SystemDataAccess = SystemDataAccessKind.None,
    IsPrecise = true,
    FillRowMethodName = "SplitFillRow",
    TableDefinintion = "s NVARCHAR(MAX)"]
public static IEnumerable Split(SqlChars seperator, SqlString s)
{
    if (s.IsNull)
        return new string[0];

    return s.ToString().Split(seperator.Buffer);
}

public static void SplitFillRow(object row, out SqlString s)
{
    s = new SqlString(row.ToString());
}

你可以这样用，

declare @desiredTags nvarchar(MAX);
set @desiredTags = 'ruby,rails,scruffy,rubyonrails';

select * from Tags
where Name in [dbo].[Split] (',', @desiredTags)
order by Count desc

可以将参数作为字符串传递

这是弦

DECLARE @tags

SET @tags = ‘ruby|rails|scruffy|rubyonrails’

select * from Tags 
where Name in (SELECT item from fnSplit(@tags, ‘|’))
order by Count desc

然后你所要做的就是将字符串作为1参数传递。

这是我使用的分裂函数。

CREATE FUNCTION [dbo].[fnSplit](
    @sInputList VARCHAR(8000) -- List of delimited items
  , @sDelimiter VARCHAR(8000) = ',' -- delimiter that separates items
) RETURNS @List TABLE (item VARCHAR(8000))

BEGIN
DECLARE @sItem VARCHAR(8000)
WHILE CHARINDEX(@sDelimiter,@sInputList,0) <> 0
 BEGIN
 SELECT
  @sItem=RTRIM(LTRIM(SUBSTRING(@sInputList,1,CHARINDEX(@sDelimiter,@sInputList,0)-1))),
  @sInputList=RTRIM(LTRIM(SUBSTRING(@sInputList,CHARINDEX(@sDelimiter,@sInputList,0)+LEN(@sDelimiter),LEN(@sInputList))))

 IF LEN(@sItem) > 0
  INSERT INTO @List SELECT @sItem
 END

IF LEN(@sInputList) > 0
 INSERT INTO @List SELECT @sInputList -- Put the last item in
RETURN
END

另一种可能的解决方案是，不向存储过程传递可变数量的参数，而是传递一个包含您要查找的名称的字符串，但通过将它们围绕在'<>'中使它们唯一。然后使用PATINDEX查找名称:

SELECT * 
FROM Tags 
WHERE PATINDEX('%<' + Name + '>%','<jo>,<john>,<scruffy>,<rubyonrails>') > 0

在我看来，解决这个问题的最佳来源是这个网站上发布的内容:

Syscomments。Dinakar Nethi

CREATE FUNCTION dbo.fnParseArray (@Array VARCHAR(1000),@separator CHAR(1))
RETURNS @T Table (col1 varchar(50))
AS 
BEGIN
 --DECLARE @T Table (col1 varchar(50))  
 -- @Array is the array we wish to parse
 -- @Separator is the separator charactor such as a comma
 DECLARE @separator_position INT -- This is used to locate each separator character
 DECLARE @array_value VARCHAR(1000) -- this holds each array value as it is returned
 -- For my loop to work I need an extra separator at the end. I always look to the
 -- left of the separator character for each array value

 SET @array = @array + @separator

 -- Loop through the string searching for separtor characters
 WHILE PATINDEX('%' + @separator + '%', @array) <> 0 
 BEGIN
    -- patindex matches the a pattern against a string
    SELECT @separator_position = PATINDEX('%' + @separator + '%',@array)
    SELECT @array_value = LEFT(@array, @separator_position - 1)
    -- This is where you process the values passed.
    INSERT into @T VALUES (@array_value)    
    -- Replace this select statement with your processing
    -- @array_value holds the value of this element of the array
    -- This replaces what we just processed with and empty string
    SELECT @array = STUFF(@array, 1, @separator_position, '')
 END
 RETURN 
END

Use:

SELECT * FROM dbo.fnParseArray('a,b,c,d,e,f', ',')

致谢:Dinakar Nethi

我将传递一个表类型参数(因为它是SQL Server 2008)，并做一个where exists，或内部连接。您也可以使用XML，使用sp_xml_preparedocument，然后甚至可以索引临时表。